Balanced chemical equation 2C8H18(g)+25O2(g)→16CO2(g)+18H2O(g) After the reaction, how much octane is left? Express your answer with the appropriate units.

Sodium carbonate, Na2CO3, is commonly used to neutralize acid spills in the laboratory. The neutralization of nitric acid is described by the UNBALANCED chemical equation HNO3 + Na2CO3 ➜ CO­2 (g) + H2O + NaNO3 How much Na2CO3 (molar mass: 105.99 g/mol) is required to neutralize 1.50 × 102 g of spilled nitric acid (molar mass: 63.01 g/mol)?   a.252 g Na2CO3 b.126 g Na2CO3 c.505 g Na2CO3 d.150 g Na2CO3

The complete combustion of gasoline (C8H18) is best represented by which of the following equations   Options:   2 C8H18 (l) + 25 O2 (g) → 16 CO2 (g) + 18 H2O(l)   2 C8H18 (l) + 17 O2 (g)  → 16 CO (g) + 9 H2O (l)   C8H18 (l) + O(g) → 8 CO2 (g) + 9 H2O (l)   C8H18 (l)  → 8 C (s) + 9 H2 (g)

The complete combustion of gasoline (C8H18) is best represented by which of the following equations:   2 C8H18 (l) + 25 O2 (g) → 16 CO2 (g) + 18 H2O(l)   2 C8H18 (l) + 17 O2 (g)  → 16 CO (g) + 9 H2O (l)   C8H18 (l)  → 8 C (s) + 9 H2 (g)   C8H18 (l) + O2(g) → 8 CO2 (g) + 9 H2O (l)   C8H18 (l) + O(g) → 8 CO2 (g) + 9 H2O (l)

The reaction of 1.0 gram of aluminum (Al) and 1.0 gram of oxygen (O2) according to the reaction below produced 1.7 grams of aluminum oxide (Al2O3). 4 Al (s) + 3 O2 (g)  → 2 Al2O3 (s)                 Calculate the theoretical yield of aluminum oxide

"You begin with 21.2 grams of CO(g) and 9.91 grams of O2(g) . If 17.48 grams of CO2(g) are produced, what is the percent yield? 2 CO(g)+ 1 O2(g) → 2 CO2(g)"

Determine the number of grams of C₄H₁₀ that are required to completely react to produce 8.70 mol of CO₂ according to the following combustion reaction:     2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(g)

Determine the amount of excess reagent (in grams) left over after 0.3893 g C6H6 reacts with 0.3914 g O2. 2 C6H6 (g) + 7 O2 (g) → 6 CO2 (g) + 6 H2O (g)

What is the mass in grams of CO₂ that can be produced from the combustion of 6.54 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(g)

The balanced equation for the combustion of butane, CaH1o, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 CAH10(g) + 13 02(g) -> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 What mass of butane, in kg, will be needed to react fully with 250 L of oxygen gas?