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When the weight of block B to maintain equilibrium is maximum, the tensile forces in the four segments of the cord are T₁, T₂, T3 and T4, as indicated in the figure. Determine the values of these four tensile forces, in N, and the mass of block B, in kg. Use g = 9.81 m/s². Draw all necessary free-body diagrams and indicate the direction of impending motion. Also, show the diagrams in finding the angle of wrap, ß for each pulley. 0.11 Pc α 30° HD 20. Y B 0.22 MB 8-60° 8-60° HC = 0.11 12 cm 30°α A HA=0.22 R 30 10 cm α P =78.93 N

When the weight of block B to maintain equilibrium is maximum, the tensile forces in the four segments of the cord are T₁, T₂, T3 and T4, as indicated in the figure. Determine the values of these four tensile forces, in N, and the mass of block B, in kg. Use g = 9.81 m/s². Draw all necessary free-body diagrams and indicate the direction of impending motion. Also, show the diagrams in finding the angle of wrap, ß for each pulley. 0.11 Pc α 30° HD 20. Y B 0.22 MB 8-60° 8-60° HC = 0.11 12 cm 30°α A HA=0.22 R 30 10 cm α P =78.93 N

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When the weight of block B to maintain equilibrium is maximum, the tensile forces in the four segments of the cord are T₁, T₂, T3 and T4, as indicated in the figure. Determine the values of these four tensile forces, in N, and the mass of block B, in kg. Use g = 9.81 m/s². Draw all necessary free-body diagrams and indicate the direction of impending motion. Also, show the diagrams in finding the angle of wrap, ß for each pulley. 0.11 = c α 30° HD 20- Y B 0.22= B 8= 60° 8 = 60° HC = 0.11 12 cm 30° α 6 cm ₁ HA=0.22 R 10 cm ➖➖➖➖➖------ α 30° P =78.93 N
Transcribed Image Text:When the weight of block B to maintain equilibrium is maximum, the tensile forces in the four segments of the cord are T₁, T₂, T3 and T4, as indicated in the figure. Determine the values of these four tensile forces, in N, and the mass of block B, in kg. Use g = 9.81 m/s². Draw all necessary free-body diagrams and indicate the direction of impending motion. Also, show the diagrams in finding the angle of wrap, ß for each pulley. 0.11 = c α 30° HD 20- Y B 0.22= B 8= 60° 8 = 60° HC = 0.11 12 cm 30° α 6 cm ₁ HA=0.22 R 10 cm ➖➖➖➖➖------ α 30° P =78.93 N
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β=θ+γ   =60+20   =80
Can u explain why the above equation is used in determining the angle of wrap and why does in all 3 pulleys u used same β

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