MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Example 7 part 1arrow_forwardI need help with this problemarrow_forwardData from a state indicate that scores on the SAT test are normally distributed with a mean of 1008 and a standard deviation of 196. Scores on the ACT test are normally distributed with a mean of 20.7 and a standard deviation of 3.8. It is assumed that the two tests measure the same aptitude, but use different scales.If a student gets an SAT score that is the 65 percentile, find the actual SAT score. Round answer to a whole number. SAT score = What would be the equivalent ACT score for this student? Round answer to 1 decimal place. ACT score = If a student gets an SAT score of 1439, find the equivalent ACT score. Round answer to 1 decimal place. ACT score =arrow_forward
- Can you answer #6?arrow_forwardThe data given below is the expected points for a football team with first down and 10 yards to go from various points on the field. In the given table x stands for the number of yards from the goal and y stands for the expected points. r = X y 5.454 5.184 25 4.702 35 3.716 45 2.612 55 2.878 65 1.778 75 0.994 85 0.792 95 -0.642 555 a) Use Desmos (watch Video if you need help) to find the equation of the least squares (regression) line. to find the coefficient of correlation. (Round to 4 decimal places as needed.) Y 15 Does there appear to be a linear correlation? O No, there is no linear correlation between the data points because r is not equal to 0. Yes, the data points show linear correlation because r is close to -1. Yes, the data points show linear correlation because r is close to 1. O No, there is no linear correlation between the data points because r is negative. b) The equation of the least squares line is (Round to 2 decimal places as needed.)arrow_forwardReview(42a): A researcher were conducted in the effect of outdoor activity on mood. She hypotthesized that spending time outdoor would increase mood. She recruited 10 participants for her study.She had each participant walk a 2km in the forest. Before and after the walk she had them rate their mood on a 5 point lukert scale with 1 very bad to 5 very good. The data is given below. Mode before Mode after 4 5 3 3 1 4 5 5 1 5 2 4 3 2 4 5 3…arrow_forward
- Using your favorite statistics software package, you generate a scatter plot which displays a linear form. You find a regression equation and the standard deviation for both variables. The standard deviation for x is 1.46, and the standard deviation for y is 5.54. The regression equation is reported as y=5.7 +1.74xy=5.7 +1.74x What fraction of the variation in y can be explained by the variation in the values of x? (Enter your answer as a decimal between 0 and 1.)arrow_forwardPlease show all work P value?arrow_forward2.2 In a population, the correlation coefficient between family income and child IQ is 0.30. The mean family income was $60,000. The standard deviation in income is $20,000. IQ is measured on a scale such that the mean is 100, and the standard deviation is 15. (a) Using this information, predict the expected IQ of a child whose family income is $70,000 (b) How reliable do you expect this prediction to be? Why? (your answer should be a property of correlation, not an opinion about IQ) (c) The family income now rises-does the correlation predict that the child will have a higher IQ? Why?arrow_forward
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