
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Transcribed Image Text:(b)
The second circuit is an active filter. If Z, is a capacitor C, and Z, is a parallel
RC circuit, with elements R and C (this C has the same value as the C in Z, ), determine an
expression for the voltage transfer function. Write your result in the form:
o« (@) _ 1+ jAo
H(@) .
V (@) 1+ jBo
in
(i.e., define A and B in terms of R and C).
Vin
Vout
Z,
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- Draw the Parallel Form implementation of the system of transfer function 1+ 32¹ 1-2z-¹ 1+ 22-1 1-3z-1 H (2) = Hint: If you put H(z) in a different form, go backward to see if you retrieve the original H(2). Warning: Beware of sign mistakes.arrow_forward1) Input signal is x(t)= 2sin(60rt)+3cos(610rt). Apply a first order analog Butterworth low-pass filter with a cutoff frequency at 100 Hz to the input. What are the output amplitudes at the two frequencies? e 2) The same signal x(t) is now digitally sampled with the sampling frequency fs=300 Hz. Output y(n)=(x[n]+x[n-1]±X[n-2])/3, what is the output signal in the time-domain?arrow_forwardYou wish to design a low pass filter using the bilinear transformation method. Your prototype normalized low pass filter's analog transfer function is given below: 1 3.98s3 +2.38s2 +3.7s +1 The cut-off frequency should be f. = 50 Hz while using a sampling frequency of F, = 2 kHz. Find: Design a digital filter that meets the above requirements. Determine H(z) for the filter. Plot the filter's magnitude and phase response. Determine the implementation equation for y[n]. Finally, assume the below signal is sampled at the given sampling frequency and is input into the digital filter. x(t) = cos(2710t) + cos(2750t)+ cos(27500t)arrow_forward
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