(b) An engineer is required to analyse a sinusoidal waveform for the voltage and current using oscilloscope. The voltage waveform produced Root Mean Square (RMS) value at 75 V with positive-going zero crossing at 30°. While the RMS value of current is 66.71 A with negative-going zero crossing at 0.349 rad. Assume the frequency of both waveforms is 50 Hz. (i) Sketch the voltage and current waveform in the same axis by showing the important point. (ii) Determine instantaneous voltage when t= 8ms - (iii) Determine phase relationship between voltage and current waveform. (c) From the measurement process, the circuit generated two different outputs, V,(t) and V,(1) with the same peak voltage. The V,(t) lagging V,(1) by 100' . If V,(1) =150sin(1000t – 40°)V , determine the RMS value and phase angle of.

(b) An engineer is required to analyse a sinusoidal waveform for the voltage and current using oscilloscope. The voltage waveform produced Root Mean Square (RMS) value at 75 V with positive-going zero crossing at 30°. While the RMS value of current is 66.71 A with negative-going zero crossing at 0.349 rad. Assume the frequency of both waveforms is 50 Hz. (i) Sketch the voltage and current waveform in the same axis by showing the important point. (ii) Determine instantaneous voltage when t= 8ms - (iii) Determine phase relationship between voltage and current waveform. (c) From the measurement process, the circuit generated two different outputs, V,(t) and V,(1) with the same peak voltage. The V,(t) lagging V,(1) by 100' . If V,(1) =150sin(1000t – 40°)V , determine the RMS value and phase angle of.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A sinusoidal waveform displayed on an oscilloscope is shown in Figure 2. The 'time/cm' switch is on 10 ms and the 'volts/cm' switch is on 5V/cm. Determine for the waveform: d) The r.m.s. value of waveform Q e) The phase difference of waveform Q relative to waveform P
3-9 An rms ac voltmeter and a peak-to-peak-reading ac voltmeter are to be used to determine whether three ac signals are sinusoidal. Deter. mine whether the signals are sinusoidal if the following readings are obtained First signal Second signal Third signal peak-to-peak reading = 35.26 V rms reading. - 12.00 V peak-to-peak reading - 11.31 V rms reading = 4.00 V peak-to-peak reading = 25.00 V rms reading -8.83 V
Q18. An AC waveform is shown in figure B3. 4 10 20 30 40 50 70 100 Time (ms) 110 -2 -3 -4 -5 Figure B3 i) For the above waveform, determine a. Peak-to-peak voltage b. Time period c. Frequency ii) For the above waveform, determine a. Peak Factor b. Form Factor
3. A sinusoidal waveform displayed on an oscilloscope is shown in Figure 2. The 'time/cm' switch is on 10 ms and the 'volts/cm' switch is on 5V/cm. Determine for the waveform: a) The frequency of both waveforms b) The peak-to-peak value of waveform Q c) The amplitude of waveform P Figure 2
a. A circuit with half-wave rectified signal has a dc voltage of 0.318Vm. The rms value of the ac component of the output signal is 0.385Vm. Calculate the percentage ripple of a half-wave rectified signal.
What is the approximate voltage amplitude and frequency of the waveform below
3. A sinusoidal waveform is displayed on a c.r.o. screen. The peak-to-peak distance is 5 cm and the distance between cycles is 4 cm. The 'time'switch is on 100 µs/cm and the 'volts/cm' switch is on 10 V/cm. Determine (i) angular frequency (ii) peak (iii) rms value of voltages (iv)Time period and (v) form factor.
3. A sinusoidal waveform is displayed on a c.r.o. screen. The peak-to-peak distance is 5 cm and the distance between cycles is 4 cm. The 'time ' switch is on 100 µs/cm and the 'volts/cm' switch is on 10 V/cm. Determine (i) angular frequency (ii) peak (iii) rms value of voltages (iv)Time period and (v) form factor.
The waveform displayed on an oscilloscope is as shown in Figure The 'time/cm' switch is set to 1 ms/cm, and the 'volts/cm' switch is set to 1 V/cm. Determine the (i) amplitude of waveform Q, (ii) peak to peak value of waveform P, (iii) frequency of waveform P and (iv) phase angle difference between P and Q in Degrees. P Upload your Answers steps in the "Final Answer Submission" Link provided in the Moodle. (i) Amplitude of waveform Q = (ii) Peak to peak value of waveform P = (iii) Frequency of waveform P = (iv) Phase angle difference between P and Q in Degrees =
The main purpose of an oscilloscope is to graph an electrical signal as it varies over time. Most scopes produce a two-dimensional graph with time on the x-axis and voltage on the y-axis. The voltage waveform on the screen looks as shown in the figure below. Here, the vertical resolution of the oscilloscope is set up to be 2 mV/division and the horizontal resolution is 2 ms/division. Time 1. Determine the peak-to-peak amplitude of the wave. Voltage
Please show the neat solution. Thank you. Draw a sinusoidal voltage waveform with peak value of 200 volts and has an instantaneous value of 100 volts at t= 1 milliseconds. The wave is increasing positively at t=0 with a magnitude of 0 volt. Calculate also the frequency and period of the said waveform.
Compare between the time-domain and frequency-domain of a sine wave signal. Assume the frequency is 8 Hz and peak values is 10 V.