B 0.75 m 1.5 m 2 m A = 300 mm? A = 250 mm2 A = 5 mm D E = 200 GPa
Q: The forces in the member BC and BD respectively are B 2m D 2m 2m 2m 10KN 2m 20 A V3 (Tensile) and v3…
A: Data given-
Q: Q/ The force in the member (CA) is 12m 50 ку 490.50 N 500.44 N 200.12 N 2550 N 5m
A: None of the options are right. but Solution is 100% right.
Q: 4. Solve the required force P. a = 2 m/s? 50 N 300 N f = 0.2 30°
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Q: 1 kN 2 kN 2 kN 2 kN 1 kN H 0.46 m F D 2.62 B I A C| E G| 2.4 m 2.4 m 2.4 m 2.4 m Figure 2
A:
Q: What are the V and M diagrams? Thanks! 50 kN 125 kN 50 kN B C D A E -0.5 m 0.3 m 0.4 m 0.2 m
A: As per the guidelines of BARTLEBY we are subjected to solve only one question at a time. Please…
Q: D 1500 N 4 m 2000 N E 4 m B A 6 m
A:
Q: 0.2 mm Alüminyum d=50 mm E-70 GPa a=23.10 1/C Oe-50 MPa Bakır d-40 mm Bakır Alüminyum E=100 GPa…
A: Bakir length = 400 mm diameter (d) = 40 mm youngs modulus (E) = 100 GPa coefficient of thermal…
Q: How much will a steel wire 2 m long and 1 mm diameter stretch under a 5 kg wt. load? (Y = 2 x 1011…
A:
Q: 5. Submit the required force P. a = 2 m/s? P 50 N 300 N 500 N f= 0.2
A:
Q: 300 N -1.35 m. -1.35 m 1.2m 1.5m 300 N 552 N 500 N
A: For solution refer below images.
Q: 2.8 m 40° 4.7 KN 2.7 m B 4.7 KN E BC=CD 2.7 m
A: A truss is a structural member, used to create rigid structures. The primary function of the truss…
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A: (I) Force has been classified on the basis of contact which is as follow 1. Contact force:- These…
Q: * Given the Modulus of elasticity of concrete 50 GPa. what is the value .of E in MPa unit O Non of…
A:
Q: -20KN/m 10kN/m 2 m -5kN 3 m A B 2 m 2 m
A: Data given - Two udl of 20 kN/m & 10 kN/m
Q: F1 = 5 kN F2 = 13 kN 0 = 45° B - 60° C F3 = 4 kN B 2 m 3. 7m F4 = 22 kN E lJa = 30° F5 = 4 kN
A: In case of multiple force on a system, resolve the forces in horizontal and vertical direction. This…
Q: 6) Modulus of Elasticity has a unit of a. Mpa b. Nm c. Nm2 d. N
A: Basics of unit Units.
Q: 20 sq mm 40 sq mm 10° W W= 40 kg stress AB = Stress AC
A:
Q: 4 kN 15 kN 45 D E F 4 m A B C 10 kN
A:
Q: rigid bar with negligible weight B 0.75 m 1.5 m 2 m A = 300 mm? A = 250 mm? A = 5 mm E = 200 GPa
A:
Q: 3 m 3 m 3 m E C 12 M= 59 N.M 13 3 4 50N D
A:
Q: 6500 N 4.5 m- 4.5 m - A 1.5 m 2 m E B
A:
Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E
A: Let RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…
Q: Aluminuni rod E 70 GP L 0.7 m A-5 cm2 Steel rod E-210 GPa L-1.4 m A=D10 cm 9 m B Fig.(5)
A: For aluminum rod (1)E1=70 GPaL1=.7 mA1=5 cm2For steel rod E2=210 GPaL2=1.4 mA2=10 cm2
Q: 6 kN 9 kNm 4 kN/m E 2 m 0.5 m 0.5 m 2 m
A:
Q: f= 1000 N/m A E+ < << - 0.7 m 0.4 m
A:
Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: 5 m/ 5 m 5 m A 20 KN B
A:
Q: 1 m 1 m 30° b. 0.5 m 0.5 m b 1m -75 mm-
A: Given Data The mass of the drum is:m=20 kg The supported diamter of frame is :D=2mm Now draw the…
Q: Which of the following nearly gives the W = 200 kN W = 400 kN 1m DI 2 m B. 5.6 m
A:
Q: C cord 2m 1.5m 10 N B. 56 N.m 2.5m E- 0.25m F 3m 1.5m 3m
A: Find the reactions at point B on member ABC
Q: B =27 a =29 y=32 e=? a=15cm FM=? b=31cm FJ=? c=65cm F=77N w=146N
A: Please see the attached solution:
Q: E= 103 GPa E = 75 GPa E= 190 GPa 0.8 mm 150 mm 100 mm 300 mm Bronze Al Steel
A: Stress produces in the material due to changes in temperature is known as thermal stress. Condition…
Q: س / استبدل نظام القوة الذي يعمل على الحزمة بقوة Bs محصلة مكافئة ولحظة عند 650 N 500 N 30° 300 N 60°…
A:
Q: 6500 N - 4.5 m– 4.5 m A 1.5 m D 2 m E B
A:
Q: 10 N 20 N 10 N E M C B 10 N 6.0m 4.0m D F A H J L 0 8 BAYS @ 3.0 m EACH 20 N • The force at member…
A:
Q: If the radius of a wire stretched by a load is doubled, then its modulus of elasticity will be (A)…
A: Modulus of elasticity or Young's modulus is defined as the slope of initial linear portion…
Q: إذا كان هناك حاجة لعزم دوران )لحظة( .P تستخدم الكماشة لإمساك نهايات أنبوب الحفر \ \ Q4: ((A و التي…
A: Note: As per the guidelines we will answer the first question for you, for the rest of the question…
Q: 3 m y 2 m 4 m В E F. AB= F(AB)=tension force in AB F. = F(AD)=tension force in AD AD F =…
A: Given : weight of the flowerpot = W= 40 N To find :Tension force magnitude in rope AE
Q: 10 N-m SN 45°. 50° F1 150 mm 30 E
A: Given Data :- F=8N AB= 450mm BC=325 mm and rest of data is in diagram.
Q: 47. The value of 1 mm of Hg is equal to А. 1.333 N/m2 В. B. 13.33 N/m2 C. 133.3 N/m 2
A: Given pressure head in mm of Hg is
Q: A 0.8 ft 4.8 ft 60 lb 3.5 ft E 48 lb 1.8 ft B |C D 3.6 ft
A:
Q: A 4-m-long beam is subjected to a variety of loadings. (a) Replace each loading with an equivalent…
A: a) (a) Let R and M are the equivalent force and moment at end A. ∑Fy=R-400-200=Ra Ra=600N ↓ Taking…
Q: Which of the following is corresponds to the force acting at member AC? E 20 k 12 ft C D 12 ft 5 k B…
A: The free body diagram of the beam is as follow:
Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: 5 m 5 m A 20 KN 5 m B
A: FAC = 23.0940 kN
Q: Example 14: An elastic rubber band is attached to points A and B as shown in Fig. Determine its…
A:
Q: F = 375 N F2 = 500 N 5 3 В. 0.5 m 8 m 6 m - 5 m- 370 F3 = 160 N
A: The given system of forces is as shown below,
Q: 600 N 300 300 F E 120 N-m 60° 60 G 200 400 200
A:
Q: а. 2.14 b. 1.75 с. 0.58 d. 1.36 e. 0.97
A: given:
Q: 7 ft докл 60° C look 50 g V 80° 140° G 6 G Jo G 66 200kN 2f1 4ft 3ft Find force for all member ? E
A: To find: The forces for all the member. FBD: The free body diagram shown below:
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- Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPaA hollow, circular, cast-iron pipe (Ec =12,000 ksi) supports a brass rod (Ec= 14,000 ksi} and weight W — 2 kips, as shown. The outside diameter of the pipe is dc= 6 in. (a) If the allowable compressive stress in the pipe is S00O psi and the allowable shortening of the pipe is 0.02 in., what is the minimum required wall thickness trmm? (Include the weights of the rod and steel cap in your calculations.) (b) What is the elongation of the brass rod Srdue to both load Wand its own weight? (c) What is the minimum required clearance h?The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe.
- A single steel strut AB with a diameter (a) Find the strut force Fs and average normal stress ds= 8 mm supports the vehicle engine hood of a in the strut. mass 20 kg that pivots about hinges at C and D (see (b) Find the average shear stress t aver in the bolt at A,figure parts a and b). The strut is bent into a loop at (C) Find the average bearing stress bon the bolt at A. its end and then attached to a bolt at A with a diameter db= 10 mm. Strut AB lies in a vertical plane.Solve the preceding problem if the mass of the tailgate is MT— 11 kg and that of the crate is hic— 6S kg. Use dimensions H = 305 mm, L = 406 mm, dc= 460 mm, and dT= 350 mm. The cable cross-sectional area is At= 11.0 mm'. (a) Find the tensile Force T and normal stress T in each cable. (b) IF each cable elongatesA spherical balloon is filled with a gas. The outer diameter of the balloon is 20 in. and the thickness is 0,012 in. Calculate the maximum permissible pressure in the balloon if the allowable tensile stress and the allowable shear stress in the balloon are 1 ksi and 0.3 ksi, respectively.
- A steel punch consists of two shafts: upper shaft and lower shaft. Assume that the upper shaft has a diameter d1= 24 mm and the bottom shaft has a diameter d2= 16 mm. The punch is used to insert a hole in a 4 mm plate, as shown in the figure. If a force P - 70 kN is required to create the hole, what is the average shear stress in the plate and the average compressive stress in the upper and lower shaft of the punch?A capped cast-iron pipe is compressed by a brass rod, as shown. The mil is turned until it is just snug, then add an additional quarter turn to pre-compress the cast-iron pipe. The pitch of the threads of the bolt ap = 52 mils (a mil is one-thousandth of an inch). Use the numerical properties provided. (a) What stresses a and arwill be produced in the cast-iron pipe and brass rod. respectively, by the additional quarter turn of the nut? (b) Find the bearing stress ahbeneath the washer and the shear stress t(in the steel cap.-7 Repeat Problem 2.3-5, but n include the weight of the bar. See Table I-I in Appendix I for the weight density of steel.
- A slightly tapered bar AB of solid circular crass section and length L is supported at end B and subjected to a tensile load P at the free end A. The diameters of the bar at ends A and B are dAand dB. respectively. Determine the length of the bar if the elongation of the bar due to the load P = 45 kips is 0.02 in. Assume that E = 10,400 ksi.Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.Repeat the previous problem using ? = 50° and stresses on the rotated element: sy1= 70 MPa, ??y1=-82 MPa, and tx1y1=-35 MPa.