Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Atmospheric air at 1 atm, 32°C, and 95 percent relative humidity is cooled to 24°C and 60 percent
relative humidity at a rate of 20 m³/min as shown in Figure Q2. A simple ideal vapor-compression
refrigeration system using refrigerant-134a as the working fluid with 0.05kg/s mass flow rate, is used
to provide the cooling required. It operates its evaporator at 4°C and its condenser at a saturation
temperature of 39.4°C. The condenser rejects its heat to the atmospheric air. Calculate:
a. the amount of water, in kg/kg dry air, removed from the air,
b. the rate of heat removed from the air, in kJ/kg dry air,
c. the rate of heat rejected at the condenser,
d. sketch the process on the psychrometric chart provided.
Expansion
valve
24°C
60%
Evaporator
-www-
Dry air mass balance:
Water mass balance:
Energy balance:
Condenser
in ₁
h= 0
Condensate
Compressor
m = m = m
I alm
Figure Q2
+ Σinh
m₂ + m₂
→Q
1
32°C
95%
m₂ = m (, -a)
= m(h, -h₂)-mh
expand button
Transcribed Image Text:Atmospheric air at 1 atm, 32°C, and 95 percent relative humidity is cooled to 24°C and 60 percent relative humidity at a rate of 20 m³/min as shown in Figure Q2. A simple ideal vapor-compression refrigeration system using refrigerant-134a as the working fluid with 0.05kg/s mass flow rate, is used to provide the cooling required. It operates its evaporator at 4°C and its condenser at a saturation temperature of 39.4°C. The condenser rejects its heat to the atmospheric air. Calculate: a. the amount of water, in kg/kg dry air, removed from the air, b. the rate of heat removed from the air, in kJ/kg dry air, c. the rate of heat rejected at the condenser, d. sketch the process on the psychrometric chart provided. Expansion valve 24°C 60% Evaporator -www- Dry air mass balance: Water mass balance: Energy balance: Condenser in ₁ h= 0 Condensate Compressor m = m = m I alm Figure Q2 + Σinh m₂ + m₂ →Q 1 32°C 95% m₂ = m (, -a) = m(h, -h₂)-mh
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