At the instant of the figure, a 3.00 kg particle P has a position vector r of magnitude 4.10 m and angle 0, = 41.0° and a velocity vector v of magnítude 7.60 m/s and angle e, = 30.0°. Force F, of magnitude 2.10 N and angle e3 = 30.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the angular momentum of the particle and (b) the torque acting on the particle? (a) Number Units kg-m^2/s (b) Number UnitsTN-m

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter3: Vectors
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Chapter 11, Problem 026
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At the instant of the figure, a 3.00 kg particle P has a position vector r of magnitude 4.10 m and angle 0, = 41.0° and a velocity vector v of magnitude 7.60 m/s and
angle e, = 30.0°. Force F, of magnitude 2.10 N and angle 03 = 30.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the
angular momentum of the particle and (b) the torque acting on the particle?
(a) Number
Units
kg-m^2/sv
(b) Number
UnitsTN-m
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Transcribed Image Text:PRINTER VERSION 4 ВАСК NEXT Chapter 11, Problem 026 Your answer is partially correct. Try again. At the instant of the figure, a 3.00 kg particle P has a position vector r of magnitude 4.10 m and angle 0, = 41.0° and a velocity vector v of magnitude 7.60 m/s and angle e, = 30.0°. Force F, of magnitude 2.10 N and angle 03 = 30.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the angular momentum of the particle and (b) the torque acting on the particle? (a) Number Units kg-m^2/sv (b) Number UnitsTN-m Click if you would like to Show Work for this question: Open Show Work
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