Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- The equilibrium constant, K., for the following reaction is 1.29×102 at 600 K. COCI,(e)=CO(g) + Cl,(g) Calculate the equilibrium concentrations of reactant and products when 0.270 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COC,] = | M [CO] M [Cl,] Marrow_forwardPhosphorus pentachloride decomposes according to the chemical equation PCI, (g) = PCI,(g) + Cl, (g) Ke = 1.80 at 250 °C A 0.1978 mol sample of PCl, (g) is injected into an empty 3.15 L reaction vessel held at 250 °C. Calculate the concentrations of PCI, (g) and PCI, (g) at equilibrium. [PCI,] = %3D [PCI,] = M %3D Question Source: MRG - General Chemistry | Pul terms of use | help about us careers privacy policy contact us N prime video P IIarrow_forwardPhosphorus pentachloride decomposes according to the chemical equation PCI, (g) = PCI, (g) + Cl, (g) K. 1.80 at 250 °C A 0.1952 mol sample of PCl, (g) is injected into an empty 2.15 L reaction vessel held at 250 °C. Calculate the concentrations of PCl, (g) and PCl, (g) at equilibrium. [PCI,] = M [PCI,] = Marrow_forward
- Use the information below to determine whether or not a reaction mixture in which the partial pressures of PCl3, Cl2, and PCl5 are 0.21 atm, 0.41 atm, and 0.59 atm, respectively, is at equilibrium at 450 K. Kp = 3.8 at 450 K.PCl3(g) + Cl2(g) -> PCl5(g) Part 1: What is the numerical value for Q for this reaction? Remember to always express your answer to correct number of significant figures. Part 2: If the reaction mixture is not at equilibrium, in which direction does the reaction proceed to achieve equilibrium?arrow_forward-2 The equilibrium constant K,, for the following reaction is 7.73×10atmat 350°C. What is the value of K. for the reaction at the same temperature? N2(g) +3H2(g)→ 2NH3(g)arrow_forwardAt 400 K, an equilibrium mixture of H2, 12, and HI consists of 0.065 mol H2, 0.079 mol 12, and 0.13 mol HI in a 4.50-L flask. What is the value of K, for the following equilibrium? (R= 0.0821 L atm/(K • mol)) 2HI(g) = H2(g) + 12(8) 0.29 8.2 0.039 O 26 3.4arrow_forward
- When the following process reaches equilibrium, does the system in question contain mostly reactants, mostly products, or fairly equal concentrations of both reactants and products? justify your answer. H2(g)+Br2(g)=2HBr(g) Kc= 1.4x10-21 at 25°carrow_forwardReferences Use the References to access important values if needed for this question. A student ran the following reaction in the laboratory at 688 K: 2HI(g) H2(g) + I½(g) When he introduced HI(g) at a pressure of 4.87 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of I2(g) to be 0.510 atm. Calculate the equilibrium constant, K,, he obtained for this reaction. %3D Submit Answerarrow_forwardThe equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K.PCl5(g) PCl3(g) + Cl2(g)Calculate the equilibrium concentrations of reactant and products when 0.246 moles of PCl5(g) are introduced into a 1.00 L vessel at 500 K. [PCl5] = M [PCl3] = M [Cl2] = Marrow_forward
- Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 1.5 L flask with 1.7 atm of ammonia gas and 2.1 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of water vapor to be 0.77 atm. Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits. K = ☐ P x10arrow_forwardDetermine the concentration of all species at equilibrium for each of the following original mixtures. At 40C K= 1.7*10^-5 2NOCl(g) ——-(reversible)—— 2NO(g) + Cl2(g) a) 2moles of NOCl 2 moles of NO 1 mole or Cl2 in 1.0L flask b) 1M concentration of all three gasesarrow_forwardAmmonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 5.0 L flask with 4.5 atm of ammonia gas and 4.5 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of water vapor to be 2.0 atm. Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits. K = | olo x10 Ar Explanation Check © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility .......................................arrow_forward
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