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Assuming the following code: int x = myfunction1(); /* arbitrary value */ int y = myfunction2(); /* arbitrary value */ int z = myfunction3(); /* arbitrary value */ //convert to double double dx = (double) x; double dy = (double) y; double dz = (double) z; unsigned ux = x; unsigned uy = y; The following statement always evaluates to 1 (True or False): dx - dy == (double) (x-y)   Question 3 options:   True   False

Assuming the following code: int x = myfunction1(); /* arbitrary value */ int y = myfunction2(); /* arbitrary value */ int z = myfunction3(); /* arbitrary value */ //convert to double double dx = (double) x; double dy = (double) y; double dz = (double) z; unsigned ux = x; unsigned uy = y; The following statement always evaluates to 1 (True or False): dx - dy == (double) (x-y)   Question 3 options:   True   False

C++ Programming: From Problem Analysis to Program Design
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter7: User-defined Simple Data Types, Namespaces, And The String Type
Section: Chapter Questions
Problem 1TF
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Assuming the following code:

int x = myfunction1(); /* arbitrary value */

int y = myfunction2(); /* arbitrary value */

int z = myfunction3(); /* arbitrary value */

//convert to double

double dx = (double) x;

double dy = (double) y;

double dz = (double) z;

unsigned ux = x;

unsigned uy = y;

The following statement always evaluates to 1 (True or False):

dx - dy == (double) (x-y)

 

Question 3 options:

  True
  False
Expert Solution
Step 1

Here we are assigning the value returned by myfunction1() to x and the value returned by myfunction2() to y.

 

dx is the double representation of x and dy is the double representation of y.

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