Assuming that the population is normally​ distributed, construct a 95​% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range.

A statistics practitioner took a random sample of 47 observations from a population whose standard deviation is 32 and computed the sample mean to be 97. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =

Exercise 1.4 (5pts). A farmer recorded the weights of 25 randomly selected pigs from his farm. A 95% confidence interval for the mean weight was calculated to be from 280.2 to 289.8 pounds. What is being estimated by this confidence interval? Choose one: a. the weights of all pigs at this farm. b. the mean weight of 25 pigs at this farm. c. the mean weight of all pigs at this farm. d. the middle 95% of weights for pigs at this farm.

Assuming that the population is normally distributed, construct a 99% confidence interval for the population mean for each of the samples below. Explain why these two samples produce different confidence intervals even though they have the same mean and range. Full data set Sample A: 1 2 2 2 7 7 7 8 Sample B: 1 2 3 4 5 6 7 8 Construct a 99% confidence interval for the population mean for sample A. (Type integers or decimals rounded to two decimal places as needed.) C

If n = 15, ¯xx¯ = 36, and s = 12, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to three decimal places.

For the data in the Excel file Education and Income, find 95% confidence intervals for the mean annual income of males and the mean annual income of females. Can you conclude that the mean income of one group is larger than the other? Education and Income               Gender Age Level of Education  Gross Annual Income  Female 40-60 Graduate Degree $75,000 Female 25-39 Bachelor's Degree $47,000 Male 40-60 High School/GED $40,000 Female 25-39 Some College $30,000 Female 25-39 Some College $60,000 Female 40-60 Bachelor's Degree $80,000 Female 25-39 Bachelor's Degree $10,000 Female 25-39 Bachelor's Degree $43,000 Male 25-39 Bachelor's Degree $130,000 Female 40-60 Bachelor's Degree $89,000 Female 40-60 Graduate Degree $50,000 Female 18-24 Some College $13,462 Female 25-39 Bachelor's Degree $85,000 Male 25-39 Bachelor's Degree $60,000 Male 40-60 Graduate Degree $200,000 Female 25-39 Associates Degree $44,000 Male 25-39 High School/GED $26,000 Male…

Person 1 Person 2 Person 3 Person 4 Person 5 Person 6 Person 7 Person 8 Person 9 Height (inches) 75 62 64 63 62 70 69 70 67 Weight (lbs) 325 250 280 220 235 265 200 365 175 (CLO 1) Construct a confidence interval to estimate the mean height and the mean weight.

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

An Internet retailer would like to investigate the relationship between the amount of time in minutes a purchaser spends on its Web site and the amount of money he or she spends on an order. The table to the right shows the data from a random sample of 12 customers. Construct a 99% confidence interval for the regression slope. Construct a 99% confidence interval for the slope. LCL = and UCL = (Round to three decimal places as needed.) C Time 20 12 28 22 1 13 Order Size $71 $23 $93 $198 $54 $35 Time 5 37 8 37 25 8 Order Size $57 $360 $122 $161 $72 $248

A statistics practitioner took a random sample of 50 observations from a population whose standard deviation is 30 and computed the sample mean to be 109. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.   A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =