If n = 22, ¯xx¯ = 36, and s = 14, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to three decimal places.

Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…

A: Sample size n =47 Sample mean=109 Population standard deviation =32

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

A:

Q: If n- 22, - 44, and s 12, construct a confidence interval at a 95% confidence level. Assume the data…

A: Solution We solve it by using excel

Q: If n = 10, ¯xx¯ = 43, and s = 8, construct a confidence interval at a 90% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n-25, -46, and s-5, construct a confidence interval at a 95% confidence level. Assume the data…

A: Givenn=25x=46s=5confidence level = 95%

Q: If n=30, (x-bar)=38, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: If n=28, (x-bar)=50, and s=10, construct a confidence interval at a 99% confidence level. Assume the…

A: Sample size n=28Sample mean=50Standard deviation =10

Q: A health researcher computed 90%, 95%, 98%, and 99% confidence intervals for the proportion of…

A: Given that a health researcher computed 90%, 95%, 98%, and 99% confidence intervals for the…

Q: If n = 22, x¯ = 34, and s = 19, construct a confidence interval at a 98% confidence level. Assume…

A:

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Given Data: Confidence level - 90%: The expression for the confidence level is,

Q: If n=14, (x-bar)=37, and s=7, construct a confidence interval at a 98% confidence level. Assume the…

A: Given,n=14x¯=37s=7degrees of freedom(df)=n-1df=14-1=13α=1-0.98=0.02α2=0.01t0.01(13)=2.650     (from…

Q: If n=10, ī(x-bar)=37, and s=19, construct a confidence interval at a 95% confidence level. Assume…

A: From the provided information, Sample size (n) = 10 Sample mean (x̄) = 37 Standard deviation (s) =…

Q: 95% confidence interval for the true percent of workers in this city who have full health insurance…

A: The question is about confidence interval.Given :Randomly selected no. of workers ( n ) = 1700No. of…

Q: If n=31, (x-bar)=49, and s=3, construct a confidence interval at a 80% confidence level. Assume the…

A: Given, Sample size = 31 Sample mean = 49 Sample standard deviation = 3   Since the population…

Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…

Q: construct a confidence interval at a 98% confidence level.

A: Given : n=29 , X-bar=39  , s=11  , α=0.02 Since , the population standard deviation (σ) is unknown.…

Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…

A:

Q: If n=13, (x-bar)=48, and s=12, construct a confidence interval at a 95% confidence level. Assume the…

A: Mean = 48Standard deviation = 12Sample size = 13

Q: If n=12, (x-bar)=33, and s=16, construct a confidence interval at a 80% confidence level. Assume the…

A:

Q: If n = 25, ¯x = 50, and s = 19, construct a confidence interval at a 99% confidence level. Assume…

A:

Q: If n = 15, ¯x = 50, and s = 9, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: Use the given data to construct a confidence interval for the population proportion p of the…

A: It is given that sample size (n) is 70  and x is 50.

Q: A statistics practitioner took a random sample of 48 observations from a population whose standard…

A: sample size(n)=48 population standard deviation(σ)=25 Mean(x)=105

Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82

A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: If n=12, x=47, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…

A: According to the provided information,

Q: If n=27, x=48, and s-6, construct a confidence interval at a 80% confidence level. Assume the data…

A:

Q: If n = 17, ¯xx¯ = 33, and s = 6, construct a confidence interval at a 99% confidence level. Assume…

A: We have, If n = 17, x¯ = 33, and s = 6, alpha=1-0.99= 0.01 Therefore  Degrees of freedom= n-1=16…

Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: If n = 18, = 46, and s = 16, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: A statistics practitioner took a random sample of 55 observations from a population whose standard…

A: It is given that, Sample mean = 104. Population standard deviation, sigma is 31. The sample size, n…

Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…

A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…

Q: If n = 41, ã=30, and s = 6, construct a confidence interval at a 80% confidence level.

A: It is given that Sample size n = 41 Sample mean = 30 Sample SD s = 6 The critical value of t at df =…

Q: If n = 180 and X = 144, construct a 99% confidence interval for the population proportion, p. Give…

A:

Q: If n = 380 and X = 304, construct a 95% confidence interval for the population proportion, p. Give…

A: Given: n = 380 x = 304

Q: If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n = 15, ¯xx¯ = 43, and s = 11, construct a confidence interval at a 98% confidence level. Assume…

A: Given that, The degree of freedom is, Critical values: The t-critical values for a two-tailed…

Q: If n = 81, -45, and s to one decimal place. = 8, construct a confidence interval at a 90% confidence…

A:

Q: A statistics practitioner took a random sample of 59 observations from a population whose standard…

A: sample size(n)=59 Population standard deviation(σ)=32 Mean(x)=95

Q: IF n=23, x-bar = 39, and s=3, find the margin of error at a 80% confidence level. Give answer to two…

A:

Q: If n=21, (x-bar)=37, and s=3, construct a confidence interval at a 90% confidence level. Assume the…

A: Given Information: Sample size n=21 Sample mean x¯=37 Sample standard deviation s=3 Confidence level…

Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…

A: We have given that,  sample mean (x̄) = 109, standard deviation (σ) = 30 and sample size (n) = 43