Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s), and state the final conclusion. Test the claim that for the population of history exams, the mean score is 80. Sample data are summarized as n-16 x-845, and s-112 Use a significance level of a-0.01. Seleccione una: O A. a = 0.01 Test statistic:t=-1,607 P-value: p = 0.8711 Critical values: t = ±1.96 Because the test statistic, t < 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O B. a = 0.01 Test statistic: t= -1.607 P-value: p = 0.1289 Critical values: t = 2.947 Because the test statistic, t < 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80. O C.a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O D. a = 0.01 Test statistic: t 1.607 P-value: p = 0.1289 Critical values: t = 1.96 Because the test statistic, t< 1.96, we do not reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the mean score is 80. O E. a = 0.01 Test statistic: t = 1.607 P-value: p = 0.1289 Critical values: t= +2.947 Because the test statistic, t< 2.947, we do not reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the mean score is 80.

Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x= 99.54, y= 98.1, r=0.931, P-value 0.000, and y = -3.01 + 1.02x, where x represents the IQ score of the younger child. Find the best predicted value of y given that the younger child has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)

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The average American gets a haircut every 38 days. Is the average larger for college students? The data below shows the results of a survey of 12 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 41, 36, 37, 39, 33, 46, 42, 35, 40, 46, 31, 40 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H1: ? V Select an answer c. The test statistic ? V (please show your answer to 3 decimal places.) |(Please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ? Va f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population mean number of days between haircuts for college students is not significantly higher than 38 at a = 0.05, so there is insufficient evidence to…