College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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ical Energy
As the car drives over the speed bump, the four springs in the
suspension compress to absorb energy. The four springs (k = 95,000
N/m) each compress 0.1000m as the car drives over the speed
bump.
The suspension in a car uses springs to absorb the shock
when a car hits a bump in the road or travels over a pothole.
Each pair of wheels has two identical springs to absorb the
energy of the car.
What is the total elastic potential energy from the four springs as the
car drives over the speed bump? Show your calculations.
A 150-kg car with a velocity of 9 m/s is traveling over a hill of
height h. At the bottom of a hill, the car hits a speed bump
Ω
without applying the brakes. The velocity of the car at the
bottom of the hill before hitting the bump is 13 m/s. The
velocity of the car as it goes over the speed bump is 12 m/s.
The car then stops at the bottom of the hill. ,
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Transcribed Image Text:ical Energy As the car drives over the speed bump, the four springs in the suspension compress to absorb energy. The four springs (k = 95,000 N/m) each compress 0.1000m as the car drives over the speed bump. The suspension in a car uses springs to absorb the shock when a car hits a bump in the road or travels over a pothole. Each pair of wheels has two identical springs to absorb the energy of the car. What is the total elastic potential energy from the four springs as the car drives over the speed bump? Show your calculations. A 150-kg car with a velocity of 9 m/s is traveling over a hill of height h. At the bottom of a hill, the car hits a speed bump Ω without applying the brakes. The velocity of the car at the bottom of the hill before hitting the bump is 13 m/s. The velocity of the car as it goes over the speed bump is 12 m/s. The car then stops at the bottom of the hill. , Review progress Question 4 of 10 + Back Next > Sign out hp
Expert Solution
Check Mark
Step 1

The potential energy stored in a spring is given by:-

U= kx2/2

Where;

k= spring Constant= 95000 N/m

x= compression of string= 0.1 m

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