As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. The bullet has a mass m, a speed v before the collision with the target, and a speed
after passing through the target. The collision is inelastic and during the collision, the amount of kinetic energy lost by the bullet and paper is equal to [(0.333)Kb BC] , that is, 0.333 of the kinetic energy of the bullet before the collision. Determine the mass M of the target and the speed V of the target the instant after the collision in terms of the mass m of the bullet and speed v of the bullet before the collision. (Express your answers to at least 3 decimals.)
V =____v
M = ___m
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps with 3 images
- Mechanic Physics: Please make sure this is right In the figure, a ball of mass m = 56 g is shot with speed vi = 23 m/s (in the negative direction of an x axis) into the barrel of a spring gun of mass M = 263 ginitially at rest on a frictionless surface. The ball sticks in the barrel at the point of maximum compression of the spring. Assume that the increase in thermal energy due to friction between the ball and the barrel is negligible. (a) What is the speed of the spring gun after the ball stops in the barrel? (b)What fraction of the initial kinetic energy of the ball is stored in the spring?arrow_forward3. Consider the following two types of completely inelastic collisions between Турe A two identical masses, m. Type A: a m m particle of mass m and velocity v strikes V a stationary target consisting of an identical particle of mass m. Type B: Туре В each particle has a mass m and a speed m m v/(22) – in this case they collide head v/2/2 V/22 on. Ignore gravity, and express your answers in terms of m and v. A. What is the speed of the center of mass for type A, and for type B collisions (before the collision occurs)? What the center of mass speed after the collision for each type of collision. Justify your answers. В. ( What is the change in the total kinetic energy for type A and type B ?arrow_forwardTwo marbles of the same mass perform a perfectly clastic and one-dimensional collision. If one of them is at rest, and the other has a speed of 4 m/s before the collision, determine the speeds after the collision.arrow_forward
- There is a large crater in Arizona called Meteor Crater. It is estimated that it was formed about 20,000 years ago by a meteorite that had a mass of about 5 x 10^10 kg and was traveling at a speed of 7.5 km/sec. How fast could this meteorite have hit the Earth (whose mass is 6 x 10^24 kg) if we assume a head-on collision?arrow_forwardThere are two relativistic particles of identical mass m that move towards each other along the same axis. The magnitudes of their momenta are the same. They collide head-on to form a new particle of mass 8m. What were the magnitudes of momenta of the initial particles?arrow_forwardA cannon of mass M fires a projectile of mass m. The energy liberated in firing is E. Assume the projectile is discharged horizontally and that the cannon is mounted on wheels of a negligible mass. Using the fact that the energy E is taken up by both cannon and projectile and that momentum is conserved in the firing, do the following: A) Find the velocity of the projectile in terms of the masses and the energy E. B) By writing the velocity of the recoiling cannon in terms of the velocity of the projectile, find a relationship between the energy liberated, E, and the energy of the projectile. C) Explain what happens as M gets very large compared to m.arrow_forward
- If 2 marbles (of same mass and speed) travel from one end of a straight line runway and strike a line of marbles, is it possible to have only one marble to pop off the other end of the line at twice the speed? Why? (explain based on momentum and kinetic energy) I tried to find the momentum for the single marble and got 2mv and found the kinetic energy to be 2mv^2 but I'm not sure if it's right or how to how to explain it if it is possible or not.arrow_forwardIn the four momentum treatment of relativistic particle collisions or decays, The mass of a particle is different for various observers. O Momentum and energy are still conserved in any inertial frame of reference. O The energy equals the sum of the momentum, pc, plus the mass, mc2. O The momentum and energy for a process are the same in all frames of reference.arrow_forwardA particle of mass M, which was initially at rest, is hit by a particle of mass m, which is travelling at the speed Vi. The two particles collide and travel in different directions at the same pace Vf. Find the mass ratio M/m in terms of ß = vi/c, assuming a relativistic, elastic collision. Demonstrate that this reduces to Vi 0, the nonrelativistic meaning.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON