College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![### Problem Statement:
A proton with a mass of \(1.672 \times 10^{-27}\) kg is traveling at a velocity of \(5.0 \times 10^6\) m/s. Calculate the momentum of the proton in Newton-seconds (N·s).
**Note:** Your answer should be expressed in the highest power possible.
### Calculation:
To find the momentum (p) of the proton, we use the formula:
\[ p = mv \]
Where:
- \( m \) is the mass of the proton (\(1.672 \times 10^{-27}\) kg)
- \( v \) is the velocity of the proton (\(5.0 \times 10^6\) m/s)
Substitute the values into the formula:
\[ p = (1.672 \times 10^{-27}\ \text{kg}) \times (5.0 \times 10^6\ \text{m/s}) \]
### Step-by-step Calculation:
1. Multiply the constants:
\[ p = 1.672 \times 5.0 = 8.36 \]
2. Multiply the powers of 10:
\[ 10^{-27} \times 10^{6} = 10^{-21} \]
So:
\[ p = 8.36 \times 10^{-21} \ \text{kg·m/s} \]
Since the SI unit for momentum is Newton-second (N·s), the final answer is already in the correct unit.
### Final Answer:
The momentum of the proton is \( 8.36 \times 10^{-21} \ \text{N·s} \).](https://content.bartleby.com/qna-images/question/d2932a05-99f3-41c1-989e-7dbca32c3377/4e3dadf4-3372-4746-bf13-2637f0e5646f/opcc3w_processed.png)
Transcribed Image Text:### Problem Statement:
A proton with a mass of \(1.672 \times 10^{-27}\) kg is traveling at a velocity of \(5.0 \times 10^6\) m/s. Calculate the momentum of the proton in Newton-seconds (N·s).
**Note:** Your answer should be expressed in the highest power possible.
### Calculation:
To find the momentum (p) of the proton, we use the formula:
\[ p = mv \]
Where:
- \( m \) is the mass of the proton (\(1.672 \times 10^{-27}\) kg)
- \( v \) is the velocity of the proton (\(5.0 \times 10^6\) m/s)
Substitute the values into the formula:
\[ p = (1.672 \times 10^{-27}\ \text{kg}) \times (5.0 \times 10^6\ \text{m/s}) \]
### Step-by-step Calculation:
1. Multiply the constants:
\[ p = 1.672 \times 5.0 = 8.36 \]
2. Multiply the powers of 10:
\[ 10^{-27} \times 10^{6} = 10^{-21} \]
So:
\[ p = 8.36 \times 10^{-21} \ \text{kg·m/s} \]
Since the SI unit for momentum is Newton-second (N·s), the final answer is already in the correct unit.
### Final Answer:
The momentum of the proton is \( 8.36 \times 10^{-21} \ \text{N·s} \).
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