A 1.672*10^-27 kg proton is traveling at (5.0x10^6) m/s. How many N.s of momentum does it have?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
### Problem Statement:

A proton with a mass of \(1.672 \times 10^{-27}\) kg is traveling at a velocity of \(5.0 \times 10^6\) m/s. Calculate the momentum of the proton in Newton-seconds (N·s).

**Note:** Your answer should be expressed in the highest power possible.

### Calculation:

To find the momentum (p) of the proton, we use the formula:
\[ p = mv \]

Where:
- \( m \) is the mass of the proton (\(1.672 \times 10^{-27}\) kg)
- \( v \) is the velocity of the proton (\(5.0 \times 10^6\) m/s)

Substitute the values into the formula:
\[ p = (1.672 \times 10^{-27}\ \text{kg}) \times (5.0 \times 10^6\ \text{m/s}) \]

### Step-by-step Calculation:

1. Multiply the constants:
   \[ p = 1.672 \times 5.0 = 8.36 \]

2. Multiply the powers of 10:
   \[ 10^{-27} \times 10^{6} = 10^{-21} \]

   So:
   \[ p = 8.36 \times 10^{-21} \ \text{kg·m/s} \]

Since the SI unit for momentum is Newton-second (N·s), the final answer is already in the correct unit.

### Final Answer:

The momentum of the proton is \( 8.36 \times 10^{-21} \ \text{N·s} \).
Transcribed Image Text:### Problem Statement: A proton with a mass of \(1.672 \times 10^{-27}\) kg is traveling at a velocity of \(5.0 \times 10^6\) m/s. Calculate the momentum of the proton in Newton-seconds (N·s). **Note:** Your answer should be expressed in the highest power possible. ### Calculation: To find the momentum (p) of the proton, we use the formula: \[ p = mv \] Where: - \( m \) is the mass of the proton (\(1.672 \times 10^{-27}\) kg) - \( v \) is the velocity of the proton (\(5.0 \times 10^6\) m/s) Substitute the values into the formula: \[ p = (1.672 \times 10^{-27}\ \text{kg}) \times (5.0 \times 10^6\ \text{m/s}) \] ### Step-by-step Calculation: 1. Multiply the constants: \[ p = 1.672 \times 5.0 = 8.36 \] 2. Multiply the powers of 10: \[ 10^{-27} \times 10^{6} = 10^{-21} \] So: \[ p = 8.36 \times 10^{-21} \ \text{kg·m/s} \] Since the SI unit for momentum is Newton-second (N·s), the final answer is already in the correct unit. ### Final Answer: The momentum of the proton is \( 8.36 \times 10^{-21} \ \text{N·s} \).
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Relativistic speed and time
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON