As seen in this Pascal's Triangle: 1 1 1 1 1 1 3 3 1 1 4 6. 4 1 Each row begins and ends with 1. Each interior entry is the sum of the two entries above it. For example, in the last row given here, 4 is the sum of 1 and 3,6 is the sum of 3 and 3, and 4 is the sum of 3 and 1. If we number both the rows and the entries in each row beginning with 0, the entry in positionk of row n is often denoted as C(n, k). For example, the 6 in the last row is C(4, 2). Given n items, C(n, k) turns out to be the number of ways number of that you can select k of the n items. Thus, C(4, 2), which is 6, is the ways that you can select two of four qiven items. So if A, B, C, and D are the four items, here are the six possible cho ices: А В, А С, A D, BС, BD, CD Note that the order of the items in each pair is irrelevant. For instance, the choice AB is the same as the choice B A.

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter4: Selection Structures
Section: Chapter Questions
Problem 14PP
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Using the picture, ultilize Java to design a container class and implement the class PascalTriangle that will generate a Pascal Triangle from a given number of rows.
Please represent each row in a triangle as a list and the entire triangle as a list of these lists, implement the class ArrayList for these lists. 
Inside this Java container class, develop a method called getChoice that takes in two parameters n and k (where n is the number for row and k is the position) and returns the integer value of C(n, k). For example, getChoices (5, 2) will return 7.



As seen in this Pascal's Triangle:
1
1
1
1
1
1
3
3
1
1
4
4
1
Each row begins and ends with 1. Each interior entry is the sum of the two
entries above it. For example, in the last row given here, 4 is the sum of 1 and
3, 6 is the sum of 3 and 3, and 4 is the sum of 3 and 1.
If we number both the rows and the entries in each row beginning with 0, the
entry in position k of row n is often denoted as C(n, k). For example, the 6 in
the last row is C(4, 2). Given n items, C(n, k) turns out to be the number of
that
you can select k of the n items. Thus, C(4, 2), which is 6, is the
ways
number of ways
that
you can select
two of four given items. So if A, B, C, and D are the four items, here are the
six possible cho ices:
А В, А С, А D, BС, В О, СD
Note that the order of the items in each pair is irrelevant. For instance, the choice
AB is the same as the cho ice B A.
Transcribed Image Text:As seen in this Pascal's Triangle: 1 1 1 1 1 1 3 3 1 1 4 4 1 Each row begins and ends with 1. Each interior entry is the sum of the two entries above it. For example, in the last row given here, 4 is the sum of 1 and 3, 6 is the sum of 3 and 3, and 4 is the sum of 3 and 1. If we number both the rows and the entries in each row beginning with 0, the entry in position k of row n is often denoted as C(n, k). For example, the 6 in the last row is C(4, 2). Given n items, C(n, k) turns out to be the number of that you can select k of the n items. Thus, C(4, 2), which is 6, is the ways number of ways that you can select two of four given items. So if A, B, C, and D are the four items, here are the six possible cho ices: А В, А С, А D, BС, В О, СD Note that the order of the items in each pair is irrelevant. For instance, the choice AB is the same as the cho ice B A.
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