using Java GUI Interface language This program is supposed to show a list of odd numbers from 1 to an upperlimitinput by the user. Run it, using an upper limit of 9. Oops! an infinite loop. Why? There are two common errorswhen using loops: First Infinite loops and Loop finish off by 1. The problem is the equals sign. I suggest usinggreater than (>) instead, it is safer!Use the debugger to set a breakpoint by clicking in the gray margin at the left edge of the code window. The linewill be highlighted in red – similar to:oddlistBox.Items.Add ("Odd Numbers:")Do Until number - upperoddListBox.Items.Add (number)Now when you start the program, it will run normally until it hits the breakpoint. Then the code window willappear and the line of code will be highlighted in yellow. The program stops before executing thehighlighted line. You can check theover the variable you are interested incan now step through the code one line at a time by pressing F8 or clicking on the 4th icon (“Step Into") in thedebug tool bar or use the menu commands. When you want to continue execution, click on the 1st("Continue") or use the shortcut keys from the menu commands.current value of a variable by hovering the mouse(e.g. number or upper) in the code window. YouDetermine why the loop is infinite and alter the code so the program works properly. What happens if the userenters an even number as the upper limit? Fix the program so it works no matter what input the user provides.

These programs can be asked from control statements, array, string, oops etc. Java basic programs…

aput by the user. Run it, using an upper limit of 9. Oops! an infinite loop. Why? There are two common errors hen using loops: First Infinite loops and Loop finish off by 1. The problem is the equals sign. I suggest using reater than (>) instead, it is safer! Jse the debugger to set a breakpoint by clicking in the gray margin at the left edge of the code window. The line ill be highlighted in red – similar to: oddListBox.Items.Add ("odd Numbers : ") Do Until number - upper

aput by the user. Run it, using an upper limit of 9. Oops! an infinite loop. Why? There are two common errors hen using loops: First Infinite loops and Loop finish off by 1. The problem is the equals sign. I suggest using reater than (>) instead, it is safer! Jse the debugger to set a breakpoint by clicking in the gray margin at the left edge of the code window. The line ill be highlighted in red – similar to: oddListBox.Items.Add ("odd Numbers : ") Do Until number - upper

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In the classic problem FizzBuzz, you are told to print the numbers from 1 to n. However,when the number is divisible by 3, print "Fizz''. When it is divisible by 5, print "Buzz''. When it isdivisible by 3 and 5, print"FizzBuzz''. In this problem, you are asked to do this in a multithreaded way.Implement a multithreaded version of FizzBuzz with four threads. One thread checks for divisibilityof 3 and prints"Fizz''. Another thread is responsible for divisibility of 5 and prints"Buzz''. A third threadis responsible for divisibility of 3 and 5 and prints "FizzBuzz''. A fourth thread does the numbers
JAVA CODE PLS THANK YOU 4. A Shorter Three by CodeChum Admin Numbers in threes are awesome! But the one last time was too lengthy to look at, so I just want to view it in a shorter but still readable format. You okay with this task? Instructions: Print out all numbers from 1 to 100 that is divisible by 3 using a for loop just like the last problem, but this time, with each number only separated by the space like that of the sample output. Output A line containing integers divisible by 3 separated by a space. 3·6·9·12·15·18·21·24...
What's wrong? for (int k = 2; k >1; k++) A. There should be a semicolon at the end of the statement B. The variable must always be the letter i when using a for loop C. The test condition makes the loop endless D. The semicolons should be commas
in java String inputWord is read from input. Write a while loop that iterates until inputWord is equal to "Finale". In each iteration of the loop: Read integer clothingNumber from input. If clothingNumber is less than 30, output the value of inputWord, followed by ": low on stock" and a newline. Otherwise, output the value of inputWord, followed by ": well stocked" and a newline. Read string inputWord from input. Click here for example 1 2 3 4 5 6 7 8 9 10 11 12 13 14 import java.util.Scanner; public class PairedDataProcessing { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); StringinputWord; intclothingNumber; inputWord=scnr.next(); /* Your code goes here */ } }
This assignment does not exactly match the one in the textbook on which it is based. I don't want any counter-controlled loops in your solution. Your solution should be able to detect when the accuracy isn't improving and then display the results of the work (as outlined below): Look at Programming Exercise **5.25 in the textbook on approximating the value of π. It is described as: π = 4 ( 1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + ... + (-1)^(i+1)/(2i-1) ) Notice that Java has the best possible value of π that can be stored as a type double available as Math.PI (part of the java.lang package). See how close you can get to the best value of π using a loop with the above technique. Notice that the above implies you are testing the value of your own estimate as it approaches the best value available in Java (as a type double). This would not be a pre-determined, counter-controlled loop. You are testing the results (sentinel-controlled) until you reach a value with the minimum discrepancy…
Exercise H for the Nested Loop Nested Loop Problems Write the program that would generate the multiplication table for numbers 1 to 10. For example: Result 1 2 3 4 5 6 7 8 9 10 2 4 6 8 10 12 14 16 18 20 3 6 9 12 15 18 21 24 27 30 4 8 12 16 20 24 28 32 36 40 5 10 15 20 25 30 35 40 45 50 6 12 18 24 30 36 42 48 54 60 7 14 21 28 35 42 49 56 63 70 8 16 24 32 40 48 56 64 72 80 9 18 27 36 45 54 63 72 81 90 10 20 30 40 50 60 70 80 90100
Write a program that asks the user to enter an integer number and checks whether the number is prime or not. Hint: A prime number (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 . . . ) is a natural number greater than 1 that has no positive divisors other than 1 and itself. To check if a number N is prime, divide it in a loop from 2 to N-1 for remainder. If remainder is never 0, then N is prime. For example, 23 and 47 are prime, but 12 and 27 are not.
You will select one of the problems below and create a program that uses nested selections to solve the problem.Do not use Boolean operators. Write a program that reads three edges for a triangle and computes the perimeter if the input is valid. Otherwise, display that the input is invalid. The input is valid if the sum of every pair of two edges is greater than the remaining edge.
Write a loop of your choice that continues to read an integer x as long as x not divisible by 5 and 3. Complete the missing code in the space provided below. { int x=1; ............ }
If you add up all the digits in 468, you get 4 + 6 + 8 = 18. The square and cube of 468 are 219024 and 102503232, respectively. Interestingly, if you add up the digits of the square or cube, you get 18 again. Are there other integers that share this property? Write a program that lists all positive integers k less than 1000 such that the three numbers k, k2, and k3 have digits that add up to the same number.
Write a do .. loop for the random number dice problem from Chap Three. Add a counter variable that is used to count the number of times this code is executed in the loop and stops after 5 times. roll = rand.nextInt(6) + 1; System.out.println(" Roll = " + roll); ctr++; using java Add a loop structure using the while loop and then add a for loop. The program should include 3 loops that do the same thing. What is the “best” loop structure to use for this problem and why?
This is my code for a random guess game and whoever has the shortest distance to number 21 wins the game. I need help with looping this game so that it would show these things:Numbers of hands played:Dealer Wins: Player Wins:and if the player randon guess is 21 the code would then exit and say thanks for playing. import random win = 21 dealer = 50 print('Player pick a number between 1-100') guess = random.randint(0,100) print('Player Guess:') print(guess) dealerdist = abs(dealer-win) playerdist = abs(guess-win) if (playerdist > dealerdist): print('Dealer Wins!') if (playerdist < dealerdist): print('Player Wins!')