Applying Kirchoff’s law to the closed loops gives the following equation for current flow in milliamperes: 2I1+ 3I2 -4I3 =26 I1-5I2-3I3 =-87 -7I1+2I2+6I3=12 Use the Gaussian Elimination method to solve for I1, I2 and I3.

Applying Kirchoff’s law to the closed loops gives the following equation for current flow in milliamperes: 2I1+ 3I2 -4I3 =26 I1-5I2-3I3 =-87 -7I1+2I2+6I3=12 Use the Gaussian Elimination method to solve for I1, I2 and I3.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Concept explainers

Nodal Analysis

In the analysis of any electric circuit, nodal analysis is the method of determining the potential difference or voltage between different nodes in an electric circuit. A node is a point where two or more branches connect each other. In the nodal analysis, the voltages are determined in the terms of branch currents. The nodal analysis is also known as the node voltage method or branch current method. The nodal analysis method is one of the several applications of Kirchhoff's Current Law (KCL).

Question

Applying Kirchoff’s law to the closed loops gives the following equation for current flow in milliamperes:
2I₁+ 3I₂ -4I₃ =26
I₁-5I₂-3I₃ =-87
-7I₁+2I₂+6I₃=12
Use the Gaussian Elimination method to solve for I₁, I₂ and I₃.

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