Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Answer Question “d”
### Heating Curve and Calculations for Water

The data provided in the table below is essential for understanding the thermal properties of water (H₂O):

| Property            | Value           |
|---------------------|-----------------|
| Melting point       | 0.0°C           |
| Boiling point       | 100.0°C         |
| Heat of Fusion      | 334 J/g         |
| Heat of Vaporization| 2260 J/g        |
| Specific Heat Capacity (solid)| 2.05 J/g°C |
| Specific Heat Capacity (liquid)| 4.18 J/g°C |
| Specific Heat Capacity (vapor) | 1.90 J/g°C |

#### 1. Heating Curve Sketch for Water
The graph provided below represents the heating curve for water, ranging from -20°C to 125°C. Below are the segments and equations used to calculate heat changes at each phase:

- **Segment A (solid heating):** 
  \[ q = m \cdot s \cdot \Delta T \]
  - From -20°C to 0°C.

- **Segment B (melting):**
  \[ q = m \cdot \Delta H_{\text{fus}} \]
  - Vertical increase at 0°C.

- **Segment C (liquid heating):**
  \[ q = m \cdot s \cdot \Delta T \]
  - From 0°C to 100°C.

- **Segment D (vaporization):**
  \[ q = m \cdot \Delta H_{\text{vap}} \]
  - Vertical increase at 100°C.

- **Segment E (vapor heating):**
  \[ q = m \cdot s \cdot \Delta T \]
  - From 100°C to 125°C.

### Additional Problems and Solutions

**b. Heat to convert 15.0 g of water at 100.0°C to steam:**

\[
q = m \cdot \Delta H_{\text{vap}} = 15 \, \text{g} \times 2260 \, \frac{\text{J}}{\text{g}} = 33900 \, \text{J}
\]

**c. Heat to convert 15.0 g of ice at 0.0°C to liquid:**

\[
q = m \cdot \
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Transcribed Image Text:### Heating Curve and Calculations for Water The data provided in the table below is essential for understanding the thermal properties of water (H₂O): | Property | Value | |---------------------|-----------------| | Melting point | 0.0°C | | Boiling point | 100.0°C | | Heat of Fusion | 334 J/g | | Heat of Vaporization| 2260 J/g | | Specific Heat Capacity (solid)| 2.05 J/g°C | | Specific Heat Capacity (liquid)| 4.18 J/g°C | | Specific Heat Capacity (vapor) | 1.90 J/g°C | #### 1. Heating Curve Sketch for Water The graph provided below represents the heating curve for water, ranging from -20°C to 125°C. Below are the segments and equations used to calculate heat changes at each phase: - **Segment A (solid heating):** \[ q = m \cdot s \cdot \Delta T \] - From -20°C to 0°C. - **Segment B (melting):** \[ q = m \cdot \Delta H_{\text{fus}} \] - Vertical increase at 0°C. - **Segment C (liquid heating):** \[ q = m \cdot s \cdot \Delta T \] - From 0°C to 100°C. - **Segment D (vaporization):** \[ q = m \cdot \Delta H_{\text{vap}} \] - Vertical increase at 100°C. - **Segment E (vapor heating):** \[ q = m \cdot s \cdot \Delta T \] - From 100°C to 125°C. ### Additional Problems and Solutions **b. Heat to convert 15.0 g of water at 100.0°C to steam:** \[ q = m \cdot \Delta H_{\text{vap}} = 15 \, \text{g} \times 2260 \, \frac{\text{J}}{\text{g}} = 33900 \, \text{J} \] **c. Heat to convert 15.0 g of ice at 0.0°C to liquid:** \[ q = m \cdot \
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