Answer question Becording to the data given. Date: Weight of cream is 326 kg. Table shows some data obtained directly from Lactascan instrument. Fat % SNF % Lacto- density 27.32 30.23 Raw milk 4.15 7.97 Skim milk 0.08 8.26 Q1. Calculate fat percent of cream A) 46 B) 28C) 32) D) 0.046 Q2. Calculate efficiency of the cream separator. A) 100% B) 98% C)97% D) 96% D) 87.2% amount 2500 L E) 0.28

Answer question Becording to the data given. Date: Weight of cream is 326 kg. Table shows some data obtained directly from Lactascan instrument. Fat % SNF % Lacto- density 27.32 30.23 Raw milk 4.15 7.97 Skim milk 0.08 8.26 Q1. Calculate fat percent of cream A) 46 B) 28C) 32) D) 0.046 Q2. Calculate efficiency of the cream separator. A) 100% B) 98% C)97% D) 96% D) 87.2% amount 2500 L E) 0.28

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Sample: Saline 0.900% (m/v), in sodium chloride (NaCl). Data: M.A. (g/mol): Na = 22.9898; K = 39.0983; Cr=51.9961; Ag = 107.8682; Cl = 35.453; N=14.0067; O = 15.9994. Material available in the laboratory's warehouse: Reagents: distilled water; standardized solution of silver nitrate (AgNO₃), at a concentration of 0.09980 mols/L; Potassium chromate solution (K₂CrO₄) 1%; ammoniacal ferric alum solution [Fe(NH₄)(SO₄)₂] and; nitrobenzene (or cooking oil, alternatively); 0.1000 mols/L potassium thiocyanate (KSCN) standard solution. Glassware: beakers of all sizes available on the market; 50, 100, 150, 200 and 250 ml Erlenmeyers; 10.00 and 25.00 mL volumetric pipettes; 15.00 mL burette; 30.00, 50.00 and 100.00 mL volumetric flasks Calculate the molarity of saline, in terms of the NaCl concentration (concentration in mols/L). (a) 0.900 mols/L (b) 5.84 mols/L (c) 0.154 mols/L (d) 0.0154 mols/L
A 0.53 g sample containing KBr (MW=119) is dissolved in 50 mL of distilled water. Titrating with 0.04614 N AgNO3 requires 28.5 mL to reach the endpoint. Calculate the %w/w KBr in the sample. (Round-off your answer to 2-decimal places) Answer = ____%
ers is or h of Part B using a control serum: 2. The following are the results of a series of bicarbonate determinations (mmol/L) run in September Calculate the: a) mean b) median 27, 25, 25, 25, 24, 24, 26, 25, 24, 25 c) mode 25 37.5? 25 d) standard deviation 24 ° ( ! ! ! ! / SY Frrrrrr gr d d 24 -24 danmun son -25 -27 25+25 format. } 251 २ 1 rithin than er the + S-SUM Rnd (-) S-VAR 2 Ran# X! d/c a b/c x" STO RCL ENG SHIF 0999 8 x10x
R:32)
A water sample was analyzed for the total hardness through the reaction between the sample and EDTA. The data obtained from the experiment are presented below (MM CaCO3 = 100.0869 g/mol): What is the ppm? 10,290 ppm 12,390 ppm 11,270 ppm 990 ppm
Which statement is correct? A) An internal standard is a different substance from the analyte. B) An internal standard is the same substance as the analyte. C) An internal standard is a same substance as the analyte matrix.
You were tasked to determine the percentages of citric acid in the freshly squeezed and bottled lemon juice. The following data were obtained. Freshly Squeezed lemon juice 13 Trials Volume of Titrant (ml) 1 25.5 Types of Lemon Juice Freshly Squezzed Bottled 12 25.5 25.5 Bottled Lemon juice 1 sate and submit. Click Saue All 18.5 Mass of 25 ml (g) 25.6 26.7 12 18.3 13 18.3 Given that the molarity of NaOH is 1.10 M (after standardization with KHP), determine the mass of citric acid in the Freshly squeezed lemon juice (8) 15°C
O B. OC. D. Which of the following is correct? OA NO INHIBITOR Km (mm) Vmax (umol)-1 sec O E. -2 -2 1/V 0.25 .8- 0.1 NO INHIBITOR Km (mm) Vmax (μmol)-1 sec 0.5 0.5 2 NO INHIBITOR Km (mm) Vmax (μmol)-1 sec 1/S (MM) 10 NO INHIBITOR Km (mm) Vmax (umol)-1 sec 0.25 2 NO INHIBITOR Km (mm) Vmax (umol)-1 sec 10 Inhibitor 2 (1 mM) Inhibitor 1 (1 mM) No inhibitor WITH INHIBITOR 1 Km (mm) -4 WITH INHIBITOR 1 Km (mm) 0.5 Vmax (μmol)-1 sec Km (mm) 0.25 WITH INHIBITOR 1 Km (mm) 0.5 0.1 Vmax (umol)-1 sec Km (mm) 0.25 WITH INHIBITOR 1 Vmax (umol)-1 sec 10 Vmax (umol)-1 sec 10 WITH INHIBITOR 1 Vmax (umol)-1 sec 2
Help 100% 47 T. "ublic Health Ch HSC 258 - Major Projec x MindTap - Cengage Lea X C The Illustration To T =55750828934189288909969212&elSBN=9781305657571&id=D1061392007&nbld=21... * Q Search t Referonces Use the References to access important values if needed for this question. For the following reaction, 50.4 grams of sulfur dioxide are allowed to react with 17.9 grams of water. sulfur dioxide (g) + water (I) sulfurous acid (H2SO3) (g) grams What is the maximum amount of sulfurous acid (H,SO3) that can be formed? What is the FORMULA for the limiting reagent? grams What amount of the excess reagent remains after the reaction is complete? Submit Answer
Help I really have no idea if I calculated it right
4
+ + HN in ethyl acetate (organic) treat with aqueous HCI Aqueous layer Organic layer treat with treat with aqueous NaOH; aqueous NaOH collect precipitate by filtration aqueous organic Final product #1 treat with "dry" with MgSO4, filter, evaporate ethyl acetate aqueous HCl; Be sure to label all glass containers of colorless solutions... collect precipitate by filtration It's easy to lose track! Final product #2 Final product #3