help solvinf for the %T, and both diluted and actual PO4s Beer's Law Plot Information Linear Regression Equation |y=664x+0.13 R- value 0.9938 Molar Absorbtivity(M'em') [0 13 Soft Drink Phosphate Data( need to to do all unknowns) Soft Drink Vol. of Soft Drink(mL) diluted [PO4 actual (PO4] Dilution %%T Absorbance Unk. Factor (иМ) 1 0.50 0.362 15 2 0.50 0.330 0.50 0.337 5

help solvinf for the %T, and both diluted and actual PO4s Beer's Law Plot Information Linear Regression Equation |y=664x+0.13 R- value 0.9938 Molar Absorbtivity(M'em') [0 13 Soft Drink Phosphate Data( need to to do all unknowns) Soft Drink Vol. of Soft Drink(mL) diluted [PO4 actual (PO4] Dilution %%T Absorbance Unk. Factor (иМ) 1 0.50 0.362 15 2 0.50 0.330 0.50 0.337 5

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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command option MOD Science 7 nt lonsns to smulov yd dne ai sw.E 179Gw 16 evbim 2ib bovloeelb lonshje lo aisii de A TASK TASK 1: Concentration of solutions that involves liguid solute and solvent uses with an equation: ni lodo Volume of % volume = Volume of biowaao1S phnswens yd wolsd 2nsmstsia srli edslgmoɔ:ar Noodeton yivlos 9onsiba Tuay rio 21swens 10oy ihV TASK 2: Directions: Choose the letter of the best answer. of a colution?
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Z question conc... → Q1/ A solution was prepared dissolving 329 mg of K,Fe(CN), in sufficient water to give 750 ml. calculate (a) the molar concentration of K. (b) The mass/volume percentage of K,Fe(CN),. mber of millimoles of K in 50.0 mL of this solution. (d) the concentration of [Fe(CN).J* in ppm. K=39 Fe=56 C=12 N=14 Q2/ calculate the p-value for each ions in the following solutions (a) 0.02 F BaCl,.2H,0 ? (b)25 ml of 0.04 M HCI mixed with 50 ml of 0.02 M NaOH
Biological studies have found that aqueous solutions containing as little as 28 µg of allicin per milliliter inhibit bacterial growth. Express this amount as the number of moles of allicin per liter of solution. \(28~\text{ug/mL}=\) \(text{mol/L}\) 20 F3 II F8 F4 F5 F6 F7 F9 F10 F11 F12 & %24 4. 3 5 7 9 { } P E T Y U %3D * CO R %23
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