and Na₂S₂O3Well#C1,D1C2,D2C3,D3126Reaction ReactionStock Stock#of # of # ofdrops drops drops Solution Solution mixing in mixing in(after (afterwell)well)HCI H₂O Na₂S,O, HCI Na,S,O, HC1 Na,S,O,406etermining the Rate Laws of the Reaction between HCl8Data Table 1. Varying Concentrations of 1.0M HC18881MConcentrations1M0.3M0.3M1M 0.3MReaction Time(seconds)Trial Trial12AverageReactionRate(sec¹)

The table given is,Rate lawRate gives the relation between the rate of reaction,rate constant and…

and Na₂S₂03 Well # C1, D1 C2, D2 C3, D3 12 6 #of # of # of Stock Stock Reaction Reaction (after (after drops drops drops Solution Solution mixing in mixing in well) well) HCI H₂O Na₂S,0, HCI Na₂S,0, HCI Na₂S,0, 4 0 6 8 Data Table 1. Varying Concentrations of 1.0M HC1 8 mining the Rate Laws of the Reaction between HC1 8 8 Concentrations 1M 0.3M 1M 0.3M 1M 0.3M Reaction Time (seconds) Trial Trial 1 2 Average Reaction Rate (sec¹)

and Na₂S₂03 Well # C1, D1 C2, D2 C3, D3 12 6 #of # of # of Stock Stock Reaction Reaction (after (after drops drops drops Solution Solution mixing in mixing in well) well) HCI H₂O Na₂S,0, HCI Na₂S,0, HCI Na₂S,0, 4 0 6 8 Data Table 1. Varying Concentrations of 1.0M HC1 8 mining the Rate Laws of the Reaction between HC1 8 8 Concentrations 1M 0.3M 1M 0.3M 1M 0.3M Reaction Time (seconds) Trial Trial 1 2 Average Reaction Rate (sec¹)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

We are given the concentration of substance A at 15 sec. (0.90 mole/L) and at 45 sec (0.30 mole/L) and asked to calculate the average rate of reaction over this time interval. а. О.003 O b. 0.30 0.2 d. 0.0004 e. 0.002 O f. 0.02
2
answer 4 through 10 blank spaces
A reaction of gas particles is given by the general equation: A(g) --> B(g). Produces the following data: Trial time (s) mole A mole B 1 1.00 0.0 20 0.66 .89 3 64 0.24 1.56 Calculate the average rate at the A disappears over trials 2 & 3.
question in image below please include all solution step by step
Energy diagrams for two reactions are shown. 150 150 100 100 50- 50- Reaction progress Reaction progress Reaction A Reaction B What is the heat of reaction for Reaction A? What is the heat of reaction for Reaction B? AHrxn A kJ AHrxn B kJ mol mol What is the activation energy for Reaction A? What is the activation energy for Reaction B? kJ kJ Ea rxn A = Ea rxn B = mol mol Energy (kJ/mol)
= For a different reaction X2Y, the initial [X] 1.0 M, and [Y] = 0 M. After 5 minutes the [X] has fallen to 0.8 M and then does not change any further. Draw a graph of [X] v time for the first 10 minutes. Use the blank template graph from Q1. Use the editor to format your answer
Which of the reactions will have a faster rate?
7. Reactions A and B were studied and found to produce the given energy diagrams. 150 150 Energy 100 (kJ/mol) 100 Energy (kJ/mol) 50 50 Reaction progress Reaction progress Reaction A Reaction B A third reaction, C was studied with a measured activation energy of 55 KJ/mol. Assume all reactions take place at the same temperature. Reaction A is slowest a. b. Reaction B is slowest c. Reaction C is slowest d. All reactions happen at the same rate.
Figure 1. Nitrite concentration versus time for the reaction of ammonium ion with nitrite ion (NO₂) = 0.00500 M nitrite concentration (M) 0.005 0.004- 0.003 0.002- 0.0011 0.000- 0 at t=0 s: d(NO₂) dt 50000 at t= 75,000 s: (NH). Critical Thinking Questions 10. What is the rate of reaction at r = 0 s? d(NO₂) di time (s) 1.35 x 10-7 M/s 100000 = 0.100 M 11. What is the rate of reaction at t = 75,000 s? 1.80 × 108 M/s 150000 12. How does the rate of reaction change as (NO₂) decreases? 13. Estimate the value of the rate of reaction at /= 175,000 s. Explain your reasoning.
7
A student follows the Determining the Rate Law for the Crystal Violet-Hydroxide lon Reaction procedure. The stock concentration of sodium hydroxide used in trial 1 is 0.021 M. The stock concentration of sodium hydroxide used in trial 2 is 0.010 M. Given the data below, what is the hydroxide ion concentration (M) in the trial 1 reaction mixture? Give your answer to four decimal places. Volume NaOH Volume Crystal Violet (mL) (mL) Trial 1 5.00 5.00 Trial 2 5.00 5.00