and et is found to be stationary. Yt=Bxt + Et t=1,2,...,T a) What are the implications of this finding? b) Write down the steps and the possible test involved in determining stationarity in êt.

Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.

Provide an analysis of the evidence emerging from tables 1 and 2

Question 18

The table below shows data on a subsample of participants in the 7th examination of the Framingham Offspring Study. Characteristic Sample Population Standard n Мean Deviation Systolic Blood 10 121.2 11.1 Pressure Diastolic Blood 10 71.3 7.2 Pressure Total Serum |Cholesterol 10 202.3 37.7 Weight 10 176.0 33.0 Height 10 67.175 4.205 Body Mass Index 10 27.26 3.10 Which of the following is the 95% confidence level for Total Serum Cholesterol 201.55, 203.05 202.15, 202.45 171.59, 233.01 178.93, 225.67

Don't copy old incorrect answers

Expain the Singer-Prebisch test/hypothesis.

The table below shows data on a subsample of participants in the 7th examination of the Framingham Offspring Study. Characteristic n Sample Population Standard Мean Deviation Systolic Blood 10 121.2 11.1 Pressure Diastolic Blood 10 71.3 7.2 Pressure Total Serum 10 202.3 37.7 Cholesterol Weight 10 176.0 33.0 Height 10 67.175 4.205 Body Mass 10 27.26 3.10 Index Which of the following is the 95% confidence level for Systolic Blood Pressure 114.32, 128.08 120.98, 121.42 121.16, 121.24 112.16, 130.24

None

Exhibit 10-1 Salary information regarding two independent random samples of male and female employees of a large company is shown below. Sample size Sampe mean salary (in $1000s) Population variance Male 64 44 128 Female 36 41 72 Refer to Exhibit 10-1. At 95% confidence, we have enough evidence to conclude that the O a. average salary of males is significantly lower than females O b. salaries of males and females are equal O c. average salary of males is significantly greater than females O d. null hypothesis fails to be rejected