Analyze the following code.public class Test {public static void main(String[] args){System.out.printlin( m(2) );public static int m( int num ) {return num;}public static void m( int num ) {System.out.printin( num );}The program has a compile error because the second m method is defmethod.The program runs and prints 2 once. public static int m( int num ){return num;}public static void m( int num ){System.out.printin( num );The program has a compile error because the second m method is defined, but not invoked in the mainmethod.The program runs and prints 2 once.O The program runs and prints 2 twice.O The program has a compile error because the two methods m have the same signature.

According to the asked question, the solution is given below with a proper explanation.

Analyze the following code. public class Test { public static void main(String[] args){ System.out.printin( m(2) ); public static int m( int num ){ return num; } public static void m( int num ) { System.out.println( num ); } The program has a compile error because the second m method is c method. O The program runs and prints 2 once.

Analyze the following code. public class Test { public static void main(String[] args){ System.out.printin( m(2) ); public static int m( int num ){ return num; } public static void m( int num ) { System.out.println( num ); } The program has a compile error because the second m method is c method. O The program runs and prints 2 once.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

10. public static void methodl (int i, int num) { for (int j = 1; j <= i; j++) { " "); System.out.print (num + num *= 2; } System.out.println(); } public static void main(String[] args) { int i = 1; while (i <= 6) { methodl (i, 2); i++; }
Examine this code and determine what happens when it is run: 1 public class Test { int x; 2 3 public Test(String t){ System.out.println("Test"); } public static void main(String[] args) { Test test = new Test ("boo"); System.out.println(test.x); } 4 5 6 7 8 10 } The program has a compile error because Test does not have a default constructor. The program has a compile error because System.out.println method cannot be invoked from the constructor. ) The program runs successfully and prints out: Test O The program has a compile error because you cannot create an object from the class that defines the object.
2. Analyze the following code: public class Test { public static void main (String[] args) { int[] x = {0, 1, 2, 3, 4, 5); xMethod(x, 5); } public static void xMethod (int[] x, int length) { for (int i = 0; i < length; i++) System.out.print(" " + x[i]); } } a. The program displays 0 1 2 3 4. b. The program displays 0 1 2 3 4 and then raises a runtime exception. c. The program displays 0 1 2 3 4 5. d. The program displays 0 1 2 3 4 5 and then raises a runtime exception. e. There is a syntax error in the declaration of xMethod
public class Turn{public static void main(String[] args){// Different initial values will be used for testingint x = 1; int y = 1; // Turn the arrow by 90 degrees System.out.print("x:", y + 90);System.out.println(x);System.out.print("y: ", x - 1 );System.out.println(y); // Turn the arrow again System.out.print("x:", y - 1);System.out.println(x);System.out.print("y: ",x + 90);System.out.println(y);}}
Analyze the following code:public class Test { public static void main(String[] args) { int[] x = {0, 1, 2, 3, 4, 5}; xMethod(x, 5); } public static void xMethod(int[] x, int length) { for (int i = 0; i < length; i++) System.out.print(" " + x[i]); }} The program displays 0 1 2 3 4 5 and then raises a runtime exception. The program displays 0 1 2 3 4 and then raises a runtime exception. The program displays 0 1 2 3 4. The program displays 0 1 2 3 4 5.
. Find the output of the following code. Public class Solution{ Public static void main(String args[]){ Int i; for(i 1; i 3) continue; } System.out.println(i); }
public class Test { } public static void main(String[] args) { String str = "Salom"; System.out.println(str.indexOf('t)); }
class operators { public static void main(String args[]) { int x = 8; System.out.println(++x * 3 + " " + x); } } Give result for the code Java Try to do ASAP ?
Identify the errors in the following code. class A { void sum(int x, int y){ System.out.println("Sum of two numbers: " +(x+y)); } void sum(int y, int x){ System.out.println("Sum of three numbers: " +(x+y)); } public static void main(String[] args){ A a = new A(); a.sum(20, 30); } }
class Lab4Q1P3 { public static void main(String args[]) { int max = 10;while (max < 10) {System.out.println("count down: " + max);max--;}}} Do you know what is wrong with the program? I know that there is error on the 7th line but I don't know what to fix.
Analyse the following code. public class Test { int x; public Test(String t) { System.out.println("Test"); } public static void main(String[] args) { Test test = new Test(); System.out.println(test.x); } } A. The program has a compile error because you cannot create an object from the class that defines the object. B. The program has a compile error because System.out.println method cannot be invoked from the constructor. C. The program has a compile error because x has not been initialized. D. The program has a compile error because Test does not have a default constructor.
Find error and correct it : public class ProgramLayout { public static void main (String[] args) { final double PI = 3.14159; double x; double sum = x+PI ; System.out.println (sum); } // end class