Analyze the following code. 1. public class Test { 2. public static void main(String[] args) { 3. Fruit[] fruits = {new Fruit(2), new Fruit(3), new Fruit(1)}; java.util.Arrays.sort(fruits); 5. } 6.} class Fruit { private double weight; public Fruit(double weight) { this.weight weight; } } The program has a compile error because the Fruit class does not have a no-arg constructor. The program has a runtime error on Line 3 because the Fruit class does not have a no-arg constructor. The program has a compile error on Line 4 because the Fruit class does not implement the java.lang.Comparable interface and the Fruit objects are not comparable. The program has a runtime error on Line 4 because the Fruit class does not implement the java.lang.Comparable interface and the Fruit objects are not comparable.
Analyze the following code. 1. public class Test { 2. public static void main(String[] args) { 3. Fruit[] fruits = {new Fruit(2), new Fruit(3), new Fruit(1)}; java.util.Arrays.sort(fruits); 5. } 6.} class Fruit { private double weight; public Fruit(double weight) { this.weight weight; } } The program has a compile error because the Fruit class does not have a no-arg constructor. The program has a runtime error on Line 3 because the Fruit class does not have a no-arg constructor. The program has a compile error on Line 4 because the Fruit class does not implement the java.lang.Comparable interface and the Fruit objects are not comparable. The program has a runtime error on Line 4 because the Fruit class does not implement the java.lang.Comparable interface and the Fruit objects are not comparable.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
![Analyze the following code.
1. public class Test {
2. public static void main(String[] args) {
3.
Fruit[] fruits = {new Fruit(2), new Fruit(3), new Fruit(1)};
4.
java.util.Arrays.sort(fruits);
5. }
6.}
class Fruit {
private double weight;
public Fruit(double weight) {
this.weight = weight;
}
}
The program has a compile error because the Fruit class does not have a no-arg
constructor.
The program has a runtime error on Line 3 because the Fruit class does not have
a no-arg constructor.
The program has a compile error on Line 4 because the Fruit class does not
implement the java.lang.Comparable interface and the Fruit objects are not
comparable.
The program has a runtime error on Line 4 because the Fruit class does not
implement the java.lang.Comparable interface and the Fruit objects are not
comparable.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F739d0479-3525-45a1-bdd9-388fdd369a1f%2F5d416128-8b29-40c7-b51a-1dc4aae7f46f%2F95jtcw_processed.png&w=3840&q=75)
Transcribed Image Text:Analyze the following code.
1. public class Test {
2. public static void main(String[] args) {
3.
Fruit[] fruits = {new Fruit(2), new Fruit(3), new Fruit(1)};
4.
java.util.Arrays.sort(fruits);
5. }
6.}
class Fruit {
private double weight;
public Fruit(double weight) {
this.weight = weight;
}
}
The program has a compile error because the Fruit class does not have a no-arg
constructor.
The program has a runtime error on Line 3 because the Fruit class does not have
a no-arg constructor.
The program has a compile error on Line 4 because the Fruit class does not
implement the java.lang.Comparable interface and the Fruit objects are not
comparable.
The program has a runtime error on Line 4 because the Fruit class does not
implement the java.lang.Comparable interface and the Fruit objects are not
comparable.
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