An X-linked gene in man is for the disorder haemophilia. This is a recessive trait. Given that a woman who is a carrier of the disorder married a normal man, what is the probability of the following occurring? show COMPLETE cross. a haemophilic son______________________________ a haemophilic daughter _______________________ a normal daughter ____________________________ a normal son __________________________________

An X-linked gene in man is for the disorder haemophilia. This is a recessive trait. Given that a woman who is a carrier of the disorder married a normal man, what is the probability of the following occurring? show COMPLETE cross. a haemophilic son__________________ a haemophilic daughter _ a normal daughter a normal son ________________

Understanding Health Insurance: A Guide to Billing and Reimbursement

14th Edition

ISBN:9781337679480

Author:GREEN

Publisher:GREEN

Chapter6: Icd-10-cm Coding

Section: Chapter Questions

Problem 170R

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Alfred is heterozygous for tongue rolling and has five fingers. Alfreda, his wife, cannot roll her tongue and is heterozygous for polydactyly. Use R/r for tounge rolling, P/p for polydactyly. What is Alfred’s genotype? ____________ What is Alfreda’s genotype? ____________
A roan bull is crossed to a white cow. The first 2 offspring turned out to be roan and white calves. Roan is a color obtained when cattle are heterozygous for the gene for red and white hairs. How is this trait inherited? _______________ Identify the genotype of the roan bull. ___________ Identify the genotype of the white cow.___________ Give the genotypic ratio. ___________________ Give the phenotypic ratio. ___________________ Show the Punnett square
10) Phenylketonuria (PKU) is a recessive disorder. Jack and Jane look normal but have a child with PKU. Therefore, what are the genotypes of Jack and Jane? __________________________________
Most autosomal recessive genetic disorders are expressed as ____________________. dominant disorders codominant loss-of-function gain-of-function
RrxRR Genotyperatioofoffspring___________________ Phenotyperatioofoffspring__________________
8) If a woman is heterozygous for neurofibromatosis (a dominant disorder) and produces with a homozygous normal man for the disorder, what are the chances that a child will have the disorder? __________________________________________________
Complete the sentences with the appropriate term. recessive retained some 25% possible 50% dominant lost all not possible The mutations found in the HD allele result in a protein that has normal activity. The pattern of inheritance of Huntington disease indicates that the HD disease allele is to the normal (HD") allele. If a mother is heterozygous for the normal and disease- causing HD alleles and a father is homozygous for the normal allele, it is all their children will have Huntington disease. Offspring of individuals that have only one parent with the mutant HD alleie have a chance of having Huntington disease.
If both parents show a recessive trait then the offspring (children) will show what? ________________________________________________________
Is the trait dominant or recessive for this pedigree? _____________. Write the genotype for each individual. (Use the letter B)
Because men only inherit one copy of the X chromosome they are said to be ______________ for geneitc traits located on the X chromosome.
Crossing over occurs during the __________________________ phase of meiosis.
sterile offspring ______________________________.