An universal coupling is used to connect two mild steel shafts transmitting a torque of 6000 N-m. Assum- ing that the shafts are subjected to torsion only, find the diameter of the shaft and the pin. The allowable shear stresses for the shaft and pin may be taken as 55 MPa and 30 MPa respectively.
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- Repeat the previous problem using ? = 50° and stresses on the rotated element: sy1= 70 MPa, ??y1=-82 MPa, and tx1y1=-35 MPa.A steel punch consists of two shafts: upper shaft and lower shaft. Assume that the upper shaft has a diameter d1= 24 mm and the bottom shaft has a diameter d2= 16 mm. The punch is used to insert a hole in a 4 mm plate, as shown in the figure. If a force P - 70 kN is required to create the hole, what is the average shear stress in the plate and the average compressive stress in the upper and lower shaft of the punch?Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPa
- Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.A flanged bolt coupling is used to connect a solid shaft 90 mm in diameter to a hollow shaft 100 mm in outsude diameter and 90 mm in inside diameter. If the allowable aring stress in the shafts and the bolts is 60 MPa, how many 10 mm diameter steel bolts must be used on a 200 mm diameter bolt circle so that the coupling will be as strong as the weaker shaft?A 75mm shaft is subjected to 5KN-m torque. Find the stress developed in MPa. Meanwhile, determine the maximum mean diameter of a taper for use to fix a lever to a shaft. If it transmit a maximum torque f 750 in-lb . The shaft diameter is in 3in
- The coefficient of friction between the belt and the pulley is 0.3 and the maximum stress in the belt is limited to 14 N/mm width. If the larger pulley rotates at 120 r.p.m., find the maximum power that can be transmitted. Q2 Find the diameter of a shaft made of 37 Mn 2 steel having the ultimate tensile strength as 600 MPa and yield stress as 440 MPa. The shaft is subjected to completely reversed axial load of 200 kN. Neglect stress concentration factor and assume surface finish factor as 0.8. The factor of safety may be takenas 1.5. Q3 a) An universal coupling is used to connect two mild steel shafts transmitting a torque of 6000 N- m. Assuming that the shafts are subjected to torsion only, find the diameter of the shaft and the pin. The allowableshear stresses for the shaft and pin may be taken as 55 MPa and 30 MPa respectively.Two 400 mm diameter pulley are keyed to a simply supported shaft 500mm apart. Each pulley is 100mm from its support and has horizontal belts tension ratio being 2.5.if the shear stress is to limited to 80MPa while transmitting 45kW at 900 r. p. m. Find the shaft diameter if it is to be used for the input - output belts being on the same or opposite sidesBearing stress 4. Please provide proper discussion and illustration also complete solution and clear solution please thank you Determine the length of a square key to be used for a 3.73 kW, 1800 rpm electric motor if the motor shaft diameter is 35 mm and the width of the key is approximately one-fourth of the shaft diameter. The allowable shearing stress on the key is 2.45 MPa
- A sleeve made of AISI 1040 CD steel has inner and outer diameters 40mm and 50mm, respectively. It is press fit on a solid shaft of same material with diameter 42mm such that the nominal diameter between sleeve and shaft became 41mm. a. Find the pressure developed between shaft and sleeve. b. Draw the tangential, radial, and total stress as a function of radius, for both sleeve and shaft. c. Find the maximum shaft diameter that can be used before failure.The shaft, is driven by pulley B from an electric motor. Another belt drivefrom pulley A is running a compressor. The belt tensions for pulley A are 1500 N and 600 N. The ratioof belt tensions for pulley B is 3.5. The diameter of pulley A is 150 mm and the diameter of pulley B is 480 mm. The allowable tensilestress for the shaft material is 170 MPa and the allowable shear stress is 85 MPa. Taking torsion andbending factors as 1.25 and 1.75 respectively, find the shaft diameter.Also find out the dimensions for a hollow shaft with outside diameter limited to 30 mm. Compare theweights of the two shafts. [Ans. 30 mm ; 24 mm ; 1.82 Given Length CD=350mm Length AB=150mm Length BD=100mm The total length is CD =3503. Find the diameter of a solid steel shaft to transmit 27 kW at 300 r.p.m. The ultimate shear stress forthe steel may be taken as 360 MPa and a factor of safety as 8. If a hollow shaft is to be used in placeof the solid shaft, find the inside and outside diameter when the ratio of inside to outside diameters is0.5