An SRS of 20 orangutans is selected, and 65 cc of blood is to be drawn from each orangutan using a 100 cc syringe. In the sample, the mean volume is 64 cc and the standard deviation is 12 cc. Assume that in the population of all such procedures, the amount of blood drawn follows a Normal distribution with mean u.

The heights of 5-year-old children are approximately normally distributed with average height of 100cm and standard deviation of 6cm. Using the emipiracal rule i am trying to figure out What percentage of 5-year-olds are between 90cm and 120cm?

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with  mean 2.65 and standard deviation 0.85.   If a random sample of 25 specimens is selected, what would be the standard error of the mean?

When samples of size 30 are collected from a normal population that has a mean of 200 and a standard deviation of 40, the standard deviation of the sampling distribution is?

The weights of 1,000 men in a certain town follow a normal distribution with a mean of 150 pounds and a standard deviation of 15 pounds.    From the data, we can conclude that the number of men weighing more than 165 pounds is about , and the number of men weighing less than 135 pounds is about .

To compare the dry braking distances from 30 to 0 miles per hour for two makes of​ automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.6 feet. The mean braking distance for Make B is 46 feet. Assume the population standard deviation is 4.5 feet. At α=0.10​, can the engineer support the claim that the mean braking distances are different for the two makes of​ automobiles? Assume the samples are random and​ independent, and the populations are normally distributed.   The critical​ value(s) is/are   Find the standardized test statistic z for μ1−μ2.

A company sells sunscreen in 500 milliliter (ml) tubes. In fact, the amount of lotion in a tube varies according to a normal distribution with mean ?=498μ=498 ml and standard deviation ?=5σ=5 ml. Suppose a store which sells this sunscreen advertises a sale for 6 tubes for the price of 5. Consider the average amount of lotion from a SRS of 6 tubes of sunscreen and find: (a) The standard deviation of the average, ?¯x¯ :  (b) The probability that the average amount of sunscreen from 6 tubes will be less than 491 ml.Answer:

To compare the dry braking distances from 30 to 0 miles per hour for two makes of​ automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 41 feet. Assume the population standard deviation is 4.6 feet.The mean braking distance for Make B is 42 feet. Assume the population standard deviation is 4.4 feet. At α=0.10​, can the engineer support the claim that the mean braking distances are different for the two makes of​ automobiles? Assume the samples are random and​ independent, and the populations are normally distributed. Complete parts​ (a) through​ (e).   (a) Identify the claim and state Ho and Ha. What is the​ claim? A.The mean braking distance is different for the two makes of automobiles. This is the correct answer. B.The mean braking distance is the same for the two makes of automobiles. C.The mean braking distance is less for Make A automobiles than Make B automobiles. Your answer is…

Given a Normal Distribution with standard error of 8 from a population with a mean of 120 and a standard deviation of 48, then find the sample size (i.e. how many people or items were sampled from the population?).

The height of an 8th grader is modeled using the normal distribution shown below. The mean of the distribution is 59.1 in and the standard deviation is 1.2 in. In the figure, Vis a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) V 56 58 60 62 Height (in inches)