An open-ended can 0.2m tall is originally full of air at 20°C. It is now immersed in water upside down, such that its top (now its bottom) is 10m below the water surface. The can is 0.2m in height. What is the density kg (k) of the air in the submerged can? Assuming the air m stays at 20°C, how high will the water rise in the can?

The density of stainless steel is about 8000 kg/m3 (eight times denser than water), but a razor blade can float on water, even with some added weights. The water is at 20oC. The blade shown in the photograph is 4.3 cm long and 2.2 cm wide. For simplicity, the center cut-out area of the razor blade has been taped so that only the outer edges of the blade contribute to surface tension effects. Because the razor blade has sharp corners, the contact angle is not relevant. Rather, the limiting case is when the water contacts the blade vertically as sketched (effective contact angle along the edge of the blade is 180°).                                                                            (a) Considering surface tension alone, estimate (in grams) how much total mass (razor blade + weights placed on top of it) can be supported. (b) Refine your analysis by considering that the razor blade pushes the water down, and thus hydrostatic pressure effects are also present. Hint: You will also…

A submarine is modeled as a cylinder with a length of 440 ft, a diameter of 50 ft, and a conning tower, as shown in the figure below. The submarine can dive a distance of 50 ft from the floating position in about 30 s. Diving is accomplished by taking water into the ballast tank so the submarine will sink. When the submarine reaches the desired depth, some of the water in the ballast tank is discharged leaving the submarine in "neutral buoyancy" (i.e., it will neither rise nor sink). 3% of cylinder 7% of cylinder volume volume 25 ft Ballast tank Partially submerged position 3 ft 146344 50 ft Y'water = 64 lb/ft³ + Totally submerged position For the conditions illustrated, find (a) the weight of the submarine and (b) the volume of the water that must be in the ballast tank when the submarine is in neutral buoyancy. For seawater, S = 1.03. (a) W = 5.866 x107 lb (b) == Water ft3

3. The tank shown in the Figure is filled with water and has a 4 cm diameter plug at the bottom on the right. There is a manometer connected to the tank on the left-hand side, filled with Mercury. All fluids are at 20°C. The safety plug will pop out if the hydrostatic force on it is 25 N. The density of the water and Mercury are pw = 998 kg/m³ and pm = 13568 kg/m³, respectively. The gravitational acceleration is g = 9.81 m/s². Mercury 2 cm H Water Plug, D = 4 cm 50⁰ a) When the plug is about to pop out, what is the distance from the centroid of the plug to the free surface of water, he? b) When the plug is about to pop out, what will be the height, h, of the mercury in the manometer?