An object takes 0.273 s to oscillate once. What is its frequency? ). If you double the frequency of an oscillator, what happens to its period?

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillations are completed in 35.5 s, the acceleration would be?

Answer..

The position of a 90 g oscillating mass is given by x(t)=A cos(10t−π/4)x(t)=A cos(10t−π/4), where ttt is in s and the amplitude A=4 cm. If necessary, round your answers to three significant figures. Determine The amplitude. The period. The spring constant. The phase constant.

0.60s A mass on a spring oscillates according to the equation v = -8.2cm/s Sin(t). What will be the velocity of the mass at t = 0.15 s? O A) 4.1 cm/s B) 8.2 cm/s C) -8.2 cm/s D) 0 cm/s

A curious physics student places an object with mass M at the end of a spring, and sets it oscillating. The student then wants to double the period of oscillation by changing the mass. They should replace the mass with:

5 kilogram object is suspended from a string. The string is 4 meters long. What is the period of the object ting as a pendulum? Express your answer a number of seconds, omitting the unit.

What frequency is depicted in the following equation of an oscillator? Assume that the units work out and the amplitude is in millimeters and the time tt is in seconds. x(t)=−2.2sin(40t−π3)x(t)=−2.2sin⁡(40t−π3) a. 6Hz6Hz b. 20πHz20πHz c. 16Hz16Hz d. 180πHz180πHz e. π20Hzπ20Hz f. 80πHz80πHz

When used on Earth, a simple pendulum oscillates with a period of 5 seconds. When used on Planet X, the same pendulum oscillates with a period of 3.6 seconds. What is the acceleration due to gravity on Planet X?

A spring with a spring constant of 200 N/m with a 5 kg mass attached to it has the following position function. ?(?) = 5 cos (0.3 ?) (The 5 has units of m and the time is in seconds.) What is the frequency of oscillation for the mass? What is the period of oscillation?