An object of mass 400 kg islocated at < 86, -25, 0> m is moving at avelocity of < 6, -9,0> m/s. Two forcesF₁ and F₂ are applied on the object. Thenet force of < 90, -75,0> N is applied for 13 s.2If F₂ = < 80, -90,0 > N, calculate1)F₁ = <21eIn the formula sheet provided,wuch equation can be used to calculate thethe impulse applied to the object? →3)The impulse applied to theobject during this 13 s interval is:Ap =<4)In the formula sheet provided,which equation can be used to calculate thefinal position of the object?5)the end of this 13 s interval is:The location of the particle at=<

Given,mass , m = 400 kg Initial position, r0 = <86,-25,0>mInitial velocity,v0 =<6,-9,0>…

An object of mass 400 kg is located at < 86, -25, 0> m is moving at a velocity of < 6, -9,0> m/s. Two forces F₁ and F₂ are applied on the object. The net force of < 90, -75,0> N is applied for 13 s.

An object of mass 400 kg is located at < 86, -25, 0> m is moving at a velocity of < 6, -9,0> m/s. Two forces F₁ and F₂ are applied on the object. The net force of < 90, -75,0> N is applied for 13 s.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 13.5 lb box is placed on the ground. (a)What force (in lb) does the ground exert on the box?…

A: Given, Weight of the block placed on the ground, W = 13.5 lb

Q: A 23.4 kg lead mass rests on the bottom of a pool. What is the normal force acting on the lead?…

Q: when a certain force is applied to an object with a mass of 2kg, its acceleration is 10.0 m/s^2.…

A: Mass of object A = 2 kg Acceleration of object A = 10.0 m/s2 Acceleration of object B = 4.0 m/s2…

Q: Only two horizontal forces act on a 3.0 kg body. One force is 90 N due east, and the other is 8N…

Q: An apple weighing 5.25 N falls from a tree. The magnitude of the force of gravity exerted on the…

A: Given that, the magnitude of the force of gravity exerted on the falling apple by the Earth is 5.25…

Q: If an applied force of 10 N directed at an angle of -30 degrees with respect to +x direction acts on…

A: Given: F = 10 N θ = - 30o with respect to + x axis mass 'm' is 3 kg We are asked to find the…

Q: move a large crate of mass 32.0 kg across a rough floor, with coefficient of kinetic friction…

A: According to Newton's second law F = ma So acceleration a = F/m

Q: When the Moon is directly overhead at sunset, the force by Earth on the Moon FEM, is essentially at…

A: We have to determine the magnitude of Moons Acceleration.

Q: A force of 15N is applied to a box in the positive horizontal direction, moving the box at a…

A: Given that the value of force and coefficient of friction.Then We have to determine the mass of the…

Q: An object of mass 200 g moving at a constant speed of 2 m/s has a net force closest to

Q: A person is pushing on a car with a force of and another person is pushing on a car with a force of…

Q: a 50 foot trailer with a weight of 8 tons is moving under a loading chute at a velocity of 3ft/sec…

A: Given information: Length of trailer = 50 ft Weight of trailer = 8 tons Velocity of trailer = 3…

Q: Boxes A and B are in contact on a horizontal, frictionless surface (Figure 1). Box A has mass 19.0…

A: Given, Box A has a mass of 19.0 kg box B has a mass of 8.0 kg A horizontal force of 130 N is exerted…

Q: A 28-N force is applied to a 5-kg object to move it with a constant velocity of 3.4 m/s across a…

A: Given Force applied on object Fa=28 N Mass of the object m=5 kg Acceleration due to gravity…

Q: Calculate the magnitude of the acceleration. Calculate the direction of the resultant force using…

A: Analyze the following figure. The applied forces can be represented in component forms as, Here, θ…

Q: . The horizontal and vertical components of several components of several forces are: (a) Pn= -200lb…

A: Magnitude of a vector A = ( Ax 2 + Ay 2 )1/2 Where Ax and Ay are x and y component.

Q: 5 ft 3 ft 2 ft- 4 ft - A |B 5 3 1213 4 5 500 lb 200 lb 260 lb

A: The resultant force in the y direction is

Q: A wagon accelerates 15.0 m/s^2 when a force of 650.0 newtons is applied to it. What is the mass of…

A: Given: Wagon acceleration, a=15.0 m/s2 Force applied, F=650 N

Q: Two forces acting on a body Fi=- 6x + 2ŷ + 52. F2= 2x + ỹ- 52, The magnitude of net force is

Q: A 50 kg object is acted upon by two forces (in N) F, = - 107 +50 7 and F, = 10 7 +50 7 What is the…

A: Given : m = 50 kg F1 = -10i + 50j F2 = 10i + 50j

Q: A claw hammer can be used both to drive nails into a piece of wood and to get them back out (see…

A: Given that: F2=50 NL=25 cm=0.25 mr=2cm=0.02 m

Q: A force of 25.0 N is applied to a 35.5 kg mass. Find: (a) The acceleration of the mass and (b) The…

A: The given data are: F=25 Nm=35 kg Here, F denotes the force and m denotes the mass.

Q: a) A 2 kg object is subjected to three forces that give it an acceleration 7…

A: Given: The mass of object is m=2 kg. The acceleration of the object is a→=-8.00 m/s2i^+6.00 m/s2j^.…

Q: A truck of mass 7 tonnes was moving with a velocity of 110 km/hr. The brakes were applied to bring…

A: The velocity of an object is defined as the rate of change of displacement with respect to time…

Q: The parachute on a race car of weight 8 820 N opens at theend of a quarter-mile run when the car is…

A: Given:Weight of the race car of the parachute = 8820 NInitial velocity = 35 m/sFinal velocity = 0…

Q: given net force, F, pushes an object of mass, m producing an acceleration, a, of the object. In a…

A: From Newtons law, for the object of mass m and acceleration a, force, F, can be given as, F=maa=Fm

Q: A 3 kg object has a velocity of 3i m/sat one instant. 8 seconds later, its velocity is (5i + 7j)…

A: mass = 3 kg initial velocity = 3 i^ msfinal velocity = 5i^ + 7j^ mstime = 8 seconds

Q: tain force is applied to a 40.0-kg object its accele

A: Given:- mass m1 = 40 kg and acceleration a1 = 12 m/s2 When the same force is applied to a different…

Q: horizontal force of 35N acting on a body of mass 5kg to move it by an acceleration of 4(m)/(s^(2)),…

Q: (25) The position vector of an object of mass 0.50 kg subject to a constant force is given by r =…

A: The mass of the given object, m=0.50 kg The position vector, r→=(at2+bt)i^+(ct2+dt)j^+(et2+ft)k^ The…

Q: The acceleration of the car is 2.5 m/s^2.the mass of the car is 6.8 kg what is the force act on the…

A: The mass of the car is The acceleration of the car is Find:What is the force acting on the car?

Q: An object of mass 10 kg is reloased trom rest 4000 m above the ground and alowed to fall undor the…

A: Given Object mass (m) = 10 kg Released from x (t) = 4000 m…

Q: A mass of 3.38 kg is on a horizontal surface. An applied force of 26.6 N at an angle of -34.5…

A: Given data: The mass of an object is, m= 3.38 kg The applied force on an object is, F = 26.6 N The…

Q: Two blocks A and B of the same mass 0.73 kg are released from rest on a 26.2° incline when they are…

Q: bus accelerates from rest until it reaches a speed of 1000 m/s. Assuming 50 s elapsed and the bus…

Q: How long would it take for a net upward force of 100.0 N to increase the velocity of a 50-kg object…

A: Force is mass times acceleration. Force and mass is given acceleration can be found using Newton's…

Q: The same force that gives the standard 1 kg mass an acceleration of 1.00 m/s^2 acts first on body A,…

Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

An object of mass 400 kg is
located at < 86, -25, 0> m is moving at a
velocity of < 6, -9,0> m/s. Two forces
F₁ and F₂ are applied on the object. The
net force of < 90, -75,0> N is applied for 13 s.
2
If F₂ = < 80, -90,0 > N, calculate
1)
F₁ = <
21e
In the formula sheet provided,
wuch equation can be used to calculate the
the impulse applied to the object? →
3)
The impulse applied to the
object during this 13 s interval is:
Ap =<
4)
In the formula sheet provided,
which equation can be used to calculate the
final position of the object?
5)
the end of this 13 s interval is:
The location of the particle at
=<

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Two blocks are in contact on a frictionless table. A horizontal force is applied to the larger block, as shown in the figure. (a) If m, - 2.6 kg. m2 = 1.4 kg, and F= 3.3N, find the magnitude of the force between the two blocks. (b) Assume instead that a force of the same magnitude Fis applied to the smaller block but in the opposite direction, and calculate the magnitude of the force between the blocks. (Why is the value calculated in (b) not the same as that calculated in (a)?) (a) Number Units (b) Number Units
A 2 kg mass of steel is placed on a slate table that has a µs of 0.2. How much force must be applied at an angle of 30° to the table in order to start the mass moving? How much force must be applied at an angle of -30° to the table in order to start the mass moving?
A mass of 2.78 kg is on a horizontal surface. An applied force of 33.5 N at an angle of -41.2 degrees with respect to the horizontal acts on the mass. What normal force does the surface exert on the mass? (Assume that gravity is in the system)
If a block of mass 889g is being pulled with a force of 2.2N parallel to a horizontal surface with a max static friction coefficient of 0.801, but the block remains at rest what is the static friction force on the block (in unit of N)?
A block of mass m,- 13.4 kg is on a frictionless table to the left of a second block of mass m,- 21.7 kg, attached by a horizontal string (see the figure below). HINT F (a) If a horizontal force of 2.13 x 102 N is exerted on the block m, in the positive x-direction, use the system approach to find the acceleration (in m/s) of the two blocks. m/s2 (b) What is the tension (in N) in the string connecting the blocks? N Need Help? Read It Watch
If 2500.0 N of force are used to stop a 6.0 x 10^4 kg train traveling 4.50 m/s, how long will it take?
A distance of 0.002m separates two objects. The first object has a mass of 25kg. If the gravitaional force between them is 0.0104 N, find the mass of the second object.
The weight (in newtons) of 600 g of grapes on the Earth is
A cat had a mass of 1000 kg and accelerates at 2 m/s^2. What bet force is exerted on the car?
the position of a 2-kg mass is given by x=2t^3-2t^2+5t. What is the net force on the mass at t=0 and t=1? (use m/s^2)
A car of mass 1650 kg is proceeding along a straight, level roat at 16m/s. The speed limit changes and the car accelerates for 7.5 seconds to a velocity of 48m/s. Find the net force propelling the car
Object 1 has a mass = 9000 kg. Object 2 has a mass = 8000 kg. If the m1m2gravitational force between them is 1 N, find the distance between them.