College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A 5.25 • 105-kg rocket is accelerating straight up. Its engines produce 1.05 • 107 N of thrust, and air resistance is 4.5 • 106 N . What is the rocket’s acceleration, using a coordinate system where up is positive?arrow_forwardDETAILS PREVIOUS ANSWERS SERPSE10 7.4.P.016. MY NOTES ASK YOUR TEACHER The force acting on a particle is F, = (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 50 20 40 10 3어 20 0,5 1.0 15 20 2,5 x (m) 30 10 -10 x (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 + x (m) 2,5 30 1아 1.5 2,0 -1어 2,5 x (m) 30 -20 0,5 1,0 15 -30 -10 - 40 -20 - 50 (b) From your graph, find the net work done by this force on the particle as x = 0 to x = 2.55 m. (Include the correct sign.) it moves from Need Help? Read Itarrow_forwardas a fish jump vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. a force chinook salmon has a length of 1.50 m and a mass of 48.5 kg. if the fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following. a. the salmon's acceleration b. the magnitude of the force F during this intervalarrow_forward
- An object is pushed in x and y directions with the force vector F=-230i+10j (N). The object weighs 20kg and goes through a displacement of r=-2i-5j (m). What would be the final velocity of the object?arrow_forwardA 2000kg truck starts at rest and reaches a speed of 15 m/s over a time period of 5s. What is the value of the force required to do this? Express answer in Newtons.arrow_forwardA freight train consists of two 8.00×104 kg5.60×104 kg engines and 45 cars with average masses of 5.50×104 kg5.50×104 kg. (a) What force must each engine exert backward on the track to accelerate the train at a rate of 4.00×10−2 m/s if the force of friction is 6.20×105 N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems. (b) What is the force in the coupling between the 37th and 38th cars (this is the force each exerts on the other), assuming all cars have the same mass and that friction is evenly distributed among all of the cars and engines?arrow_forward
- A bowling ball weighing 46.5 N initially moves at a speed of 5.10 m/s. How long must a force of 44.5 N be applied to the ball to stop it?arrow_forwardAt Ted's request, Bill pushes the pizza box across the granite countertop towards Ted. When the box leaves Bill's hand it is sliding at 2.60 m/s. The box comes to rest over a distance of 110 cm. What is the coefficient of kinetic friction, uk, between the pizza box and the countertop? (Ignore air drag.)arrow_forwardA boy, with a mass of 48.0 kg, rides a skateboard with a mass of 3.00 kg on a horizontal road. At the top of an incline, his velocity is 1.30 m s. He rides down the incline and reaches the bottom with a velocity of 3.40 m s. The difference in height between the top and the bottom of the incline is 0.540 m. Calculate the average resistive force while the boy rode down the incline. 1.30 m/s तं 3.40 m/s तं 0.540 m 38.0 marrow_forward
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