College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x = 5.0 sin (rt + t/3). The velocity (in m/s) of the body at t = 1.0 s is О -14 +8.0 -8.0 O +14 О-5.0arrow_forwardA large block with mass 18 kg executes horizontal simple harmonic motion as it slides across a frictionless surface with a frequency 1.27 Hz. Block smaller block with mass 5 kg rests on it, as shown in the figure, and the coefficient of static friction between the two is flg = 0.401. The acceleration of gravity is 9.8 m/s². k -0000² 25 5 kg s=0.401 18 kg What maximum amplitude of oscillation can the system have if the block is not to slip? Answer in units of cm.arrow_forwardAn object exhibiting simple harmonic motion has its position defined by the equation y = 5.00 sin (2t + pi/2) in meters. Find the acceleration of the particle at t = 2.81 s. (Hint: Find the second derivative of the position with respect to time and replace the value of t in the expression).arrow_forward
- The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where x is in meters and t is in seconds. At x = 0, the particle's velocity is v = -1.256 m/s. The period of oscillation, T, equals: 0.25 sec 3 sec 1.5 sec 1sec 0.5 secarrow_forwardA simple harmonic motion is give by y = 12m * cos(8t) . What is the maximum acceleration in m/s^2?arrow_forwardAn object is undergoing simple harmonic motion with period 1.250 s and amplitude 0.650 m. At t = 0 the object is at x = 0 and is moving in the negative x-direction. How far is the object from the equilibrium position when t = 0.485 s?arrow_forward
- The amplitude of an object in simple harmonic motion is 4.00 m. Its maximum acceleration is 5.00 m/s². What is the period of the simple harmonic motion? O 0.417 s O 5.03 s O 5.62 s O 1.25 s 0.800 s O none of the abovearrow_forwardA piston in a gasoline engine oscillates with simple harmonic motion. The displacement of the piston varies according to x(t) = (6.00 cm) cos (2t + ), where x is in cm and t is in seconds. At t= 0, find: i) the position of the particle, ii) its velocity, iii) its acceleration, iv) the period, and v) the amplitude.arrow_forward75. A person bounces up and down on a trampoline, while always staying in contact with it. The motion is simple harmonic motion, and it takes 1.90 s to complete one cycle. The height of each bounce above the equilibrium position is 45.0 cm. Determine (a) the amplitude and (b) the angular frequency of the motion. (c) What is the maximum speed attained by the person?arrow_forward
- The graph shows the position of an object in simple harmonic motion. At which labeled point is the instantaneous velocity zero while the acceleration is in the negative direction? A O A OB O E O с x (m) D B 1 2 3 D E t(s)arrow_forwardThe graph shows the x-displacement as a function of time for a particular object undergoing simple harmonic motion. This function can be described by the following formula:x(t) = Acos(ωt+φ)where x and A are measured in meters, t is measured in seconds, ω is measured in 1/s and φ is measured in radians. A=2.90m, T=4.00s, ω=1.57 1/s, f=2.50*10^-1 Hz Determine the phase constant i.e. find the smallest positive value for φ.arrow_forwardThe function x = (6 m) cos[(4π rad/s)t + π/8 rad] gives the simple harmonic motion of a body. At t =3 s, what are the (a) acceleration, and (b) phase of the motion?arrow_forward
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