An object moves in simple harmonic motion described by d = 4 sin 5t, where t is measured in seconds and d in meters. Find a. the maximum displacement; b. the frequency; and c. the time required for one cycle.

3. A 20 g block is attached to a spring and oscillates at 2.0 Hz. At one instant, the block is at x = 5.0 cm and has a velocity v = -30 cm/s Find the amplitude and the period of the motion.

4. A mass, m, is suspended from a vertically oriented spring, with constant, k. A downward impulse, J, is delivered to the mass, driving the spring-mass system into oscillatory motion. Express all answers in terms of given quantities and fundamental constants. a. What is the speed of the mass immediately after delivery of the impulse? Answer 4a: b. What is the amplitude of motion? Page 3 I 6 +

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An object exhibiting simple harmonic motion has its position defined by the equation y = 5.00 sin (2t + pi/2) in meters. Find the acceleration of the particle at t = 2.81 s. (Hint: Find the second derivative of the position with respect to time and replace the value of t in the expression).

8. A pendulum with a length of 1.00 m is released from an initial angle of 15.0°. After 1 000 s, its amplitude has been reduced by friction to 5.50°. What is the value of b/2m?

An object is undergoing simple harmonic motion with frequency f = 5.3 Hz and an amplitude of 0.11 m. At t = 0.00 s the object is at x = 0.00 m. How long does it take the object to go from x = 0.00 m to x = 8.00×10−2 m. A 2.27×10−2 seconds B 0.154 seconds C 2.45×10−2 seconds D 1.31×10−2 seconds

3. A simple harmonic oscillator consists of a block attached to a spring with k = 200 N/m. The block slides on a frictionless surface, with equilibrium point x = 0 and amplitude 0.20 m. A graph of the block's velocity v as a function of time t is shown. The horizontal scale is set by t, = 0.20 s.What v (m/s) t (s) are -2n the period of the SHM the block's mass а. b. it's displacement at t = 0 it's acceleration at t = 0.10 s, and it's maximum kinetic energy? С. d. е.

The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where x is in meters and t is in seconds. At x = 0, the particle's velocity is v = -1.256 m/s. The period of oscillation, T, equals: 0.25 sec 3 sec 1.5 sec 1sec 0.5 sec

A particle executes simple harmonic motion with an amplitude of 5.00 cm. At what positions does its speed equal one third of its maximum speed? larger number cm smaller number cm