An electron moving with a velocity, v =(4.0 i+ 3.0 j+ 2.0k) x 10^6m/s enters a region where there is a uniform electric field and a uniform magnetic field. The magnetic field is given by B =(1.0 i − 2.0 j + 4.0k) x 10^−2T. If the electron travels through a region without being deflected, what is the electric field?

A particle with positive charge q moves with a velocity v = (51 + 2ĵ- k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. Let B = (3î + 5ĵ + Â) T and Ể = (E¸î + Eĵ + E₂Â) V/m. For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) Ex = 7 x V/m Ey = X V/m E₂ = V/m 10

An electron (q = -1.6 x10-19 C, m = 9.1x10-31 kg) moves in an uniform magnetic field B= 0.5 Ti . At t=0 the electron has velocity components Vx = 2x105 m/s and Vy = 1x105 m/s and Vz= 0 m/s. in addition the magnetic field there is an electric field E = 2 x 104 iV/m. I. What is the net force acting on the electron at t=0 (direction and magnitude) II. What is the trajectory of the electron. Explain  III. How long does the electron take to make a complete circle  IV. What is the pitch of the electron

An electron (me = 9.11 x 1031 kg, q = -1.602 x 10-19 C) travels at 3.0 x 10' m/s perpendicular to a 1.2 mT magnetic field. What is the magnitude of the electron's acceleration in m/s? Give your answer as only the numerical value in the Sl units specified. e is interpreted as x10^ for use with large or small values; 1.01e2 is interpreted as 1.01 x 102.

A proton is accelerated in a particle accelerator from rest through a potential difference of 0.130 kV. If the proton then passes through a uniform magnetic field of magnitude 0.120 T that is perpendicular to the proton's path, what is the radius of the path that the proton will take through the magnetic field? Give your answer in cm. (The mass of a proton is 1.672*10^-27 kg.)

A proton moves at a speed 1.6 × 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.975 m. What is the field strength, in tesla?

A 3-D magnetic field vector with components of Bx = 3.34 mT; By = -10.3 mT; Bz = 4.13 mT such that the full vector in unit vector notation is written as  .B=Bx i + By j + Bz k What is the magnitude of this vector in units of Tesla (the unit of magnetic field in SI units)?

The figure below shows two wires carrying currents of I = 4.55 A in opposite directions, separated by a distance d. Assume d = 8.3 cm. (a)Find the magnitude (in µT) and direction of the net magnetic field at a point halfway between the wires. what is the magnitude µTdirection, (b)Find the magnitude (in µT) and direction of the net magnetic field at point P1, 8.3 cm to the right of the wire on the right. magnitude µTdirection, (c)Find the magnitude (in µT) and direction of the net magnetic field at point P2, 2d = 16.6 cm to the left of the wire on the left. magnitude µTdirection, (d) What If? Repeat parts (a) through (c) for the case where both wires carry currents in the same direction, upward in the figure.Find the magnitude (in µT) and direction of the net magnetic field at a point halfway between the wires. magnitude µTdirection, Find the magnitude (in µT) and direction of the net magnetic field at point P1, 8.3 cm to the right of the wire on the right. magnitude µTdirection, Find…

A very long straight wire carrying an electric current is perpendicular to the x-y plane. The current has a value of 26.7 A and is directed in the +z (out of the page). At point 'p', the magnetic field B is represented by one of the arrows. y (cm) 9 8 7 6 5 4 3 2 1 0 0 1 2 3 4 5 6 7 8 9 10 wire U T x (cm) Indicate the direction of the magnetic field at point 'p'. T: The direction of the magnetic field is .... Previous Tries You are correct. Your receipt no. is 158-4654 Calculate the magnitude of the B-field at 'p'. 1.78x10^-4 Submit Answer Units required. Units required. Tries 1/99 Previous Tries Calculate the x-component of the B-field at 'p'. Submit Answer Tries 0/99

You have placed electrons in a magnetic field. The electrons move in horizontal circles of radius 9.5 cm when their speed is 2.0×10^6 m/s. What is the magnitude and direction of the magnetic field that causes this motion?