College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron is to be accelerated in a uniform electric field having a strength of 2x10^6 V/m. Calculate: a) What energy in keV is given to the electron if it is accelerated through 0.4 m?arrow_forwardand F represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of F/F is of the order of e (a) 1042 (c) 1024 (b) 10-²1 F g (d) 10-43 KALarrow_forwardA particle (q = 5 mC, m 5 mC, m = 20 g) has a speed of 13 m/s when it enters a region where the electric field has a constant magnitude of 43 N/C and a direction that is the same as the speed of the particle What is the particle's velocity 5 s after it enters this region? From your answer without a decimal place.arrow_forward
- An electron is moving east with a speed 6.00 x 10° m/s in a uniform electric field. Magnitude of the electric field is 2.00 N/C directed to the west. What is the speed of the electron when it travels 0.50 m in the east direction? Please write your answer in km/s.arrow_forwardA proton has a mass of about 1.673x10-27kg. If an electron is placed in a region of space within which a constant electric field exists with magnitude 4.156 N/C, how long would it take this proton to travel a distance of 649.72m in units of ms (milliseconds)? Assume the proton does not collide with anything along the way. Hint: You will need to use the kinematic relationships for linear motion that we learned back in PHY 2010. This results of this problem show you that small charges like protons, and electrons too, move great distances in a short amount of time under very small external electric fields - if those charges are in a vacuum - otherwise, they quickly strike a nearby charge.arrow_forwardA constant electric field accelerates a proton from rest through a distance of 1.90 m to a speed of 1.57 × 10^5 m/s. ( The mass and charge of a proton are mp= 1.67×10^-27 kg ans qp= e= 1.60 × 10^-19 C.) a) Find the change in the protons kinetic energy ( in J). b) Find the change in the system's electric potential energy ( in J). c)Calculate the magnitude of the electric field ( in N/C).arrow_forward
- A proton with speed v =3×105×105m/s orbits just outside a charged sphere of radius r =1 cm. The charge on the sphere is:arrow_forwardCalculate the gravitational force between these two protons. Newton’s gravitational constant is 6.7 × 10−11 N · m2 /kg2 and the mass of the proton is 1.7 × 10−27 kg. Answer in units of N.arrow_forwardBeams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. (a) What acceleration would a proton experience if the gun's electric field were 2.96 × 104 N/C? (b) What speed would the proton attain if the field accelerated the proton through a distance of 0.875 cm?arrow_forward
- An electron is to be accelerated in a uniform electric field having a strength of 2.3·106 Vm. a) What energy in keV is given to the electron if it is accelerated through 0.35 m? b) Over what distance (in km) would it have to be accelerated to increase its energy by 58 GeV?arrow_forwardA proton accelerates from rest in a uniform electric field of 590 N/C. At one later moment, its speed is 1.00 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. 5.65e10 v m/s? (b) Over what time interval does the proton reach this speed? 1.79e-8 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. s (c) How far does it move in this time interval? 8.85e-6 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m (d) What is its kinetic energy at the end of this interval? 8.35e-22 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Jarrow_forwardAn electron flies into a constant electric field (along the direction of the lines of E-field). The initial electron velocity is 10 km/s. Calculate the magnitude the electric field if the electron stops in 6 nsec. The electron mass is me =9.11×10-31 kg, the electron charge is qe = -1.61×10-19 C. The electric field, E = Units .arrow_forward
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