College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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An electron beam is accelerated horizontally from the rest by a potential difference of 450V.
If the beam then enters a perpendicular uniform electric field between two parallel plates, calculate
i) the speed of the electron as it enters the field
ii) the kinetic energy of the electron
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- Two parallel plates are separated by 2.50cm and connected to a 120V battery. a)What is the magnitude of the existing field between the plates? b)How much work is done on a proton to move it from the positive plate to the negative plate if it starts from rest and it moves horizontally? c)How much is the electric force acting in the proton? d)How much is its acceleration? e)With what speed does it reach the negative plate?arrow_forwardIf a proton is accelerating from rest in a smooth electric field of 480 N / C, what is the kinetic energy of this proton at t = 1.3x10 ^ -5s? (Calculate by a factor of x10 ^ -15 J) A) 0.8 C) 1.4 B) 1.7 D) 0.3 E) 1.0arrow_forward-A ZE The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.3 cm, find the magnitude of the uniform electric field in the region between the plates. N/Carrow_forward
- (Mulitple choice) If we move a negatively charged particle through an electric field, in which situation is there no change in the electric potential energy of the particle? (explain why that answer is correct) a. We move the particle in the direction of the electric field b. We move the particle in the direction opposite that of the electric field c. We move the particle perpendicularly to the direction of the electric fieldarrow_forwardc) Considering electron and proton as two charged particles separated by d = 5 × 10-11 m calculate the following: i) the electrostatic potential at a distance d from the proton. ii) the potential energy of the electron in the field of the proton iii) the Coulomb force between proton and electron iv) the gravitational force between the proton and electron and find its ratio to the Coulomb force. Take the mass of the proton 1.7 x 10-27 kg, the mass of the electron 9.1 x 10-31 kg, the electron charge -1.6 x 10-19 C, the value of the universal gravitational constant 1 6.7 × 10-11 N kg-2m-2 and Απο 9 x 10° m/F.arrow_forwardBefore liquid crystal display LCD computer and television screens, the screens were cathode-ray tube CRTS, in which a bean of electrons was shot towards a Phosphorescent screen at high speed and deflected by electric fields in order to direct the beam to the right place on the screen so that it would form the picture. In a typical television, the speed of the electrons is 1 x10^8 m/s. If the television set is placed so that the CRT beam is horizontal heading east in a place where the earths magnetic field is 5×10^-5 and points horizontally northward what will be the magnetic force on the electron?arrow_forward
- Q20))Calculate the electrical potential at a point 12 cm from the center of a properly charged disc with surface charge density σ = 1.2 nC / m² and radius 5 cm.A) 0.467 VB) 0.678 VC) 0.231 VD) 0.325 VE) 0.538 Varrow_forwardPart i, ii and iiiarrow_forward(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 154 V. m/s (b) Calculate the speed of an electron that is accelerated through the same potential difference. m/s Need Help?arrow_forward
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