An electrochemical cell is constructed using a silver electrode immersed in a saturated silver sulphate solution and a standard hydrogen electrode. Write the anode equation of this cell. Write the cell notation of the electrochemical cell. Write the overall cell reaction equation. Determine the concentration of the silver ions (3 significance figure) in the silver half-cell if the e.m.f of the electrochemical cell is +0.78 V. Given [H*]= 1.00 moldm3

A standard galvanic cell is constructed in which a Ni?* | Ni half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) O Ni is oxidized at the cathode. Ni2+ is reduced at the cathode. The anode reaction could be Fe -> Fe2+ + 2e The anode compartment could be I2|I". As the cell runs, anions will migrate from the Ni²"|Ni compartment to the other compartment.

Calculate Ecell (volts) for the galvanic cell containing the reaction shown below where the concentration of the ion at the anode is 0.500 M and the concentration of the ion at the cathode is 1.50 M. Use the standard reduction potentials from Appendix L in our textbook.

Calculate Ecel (volts) for the galvanic cell containing the reaction shown below where the concentration of the ion at the anode is 0.793 M and the concentration of the ion at the cathode is 1.90 M. Use the standard reduction potentials from Appendix L in our textbook. Np + Lu³* » Lu + Np3*

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A certain half-reaction has a standard reduction potential E=+1.34 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.20 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer reguires this half-reaction to happen at the anode of the cell. nh Data Half-Reaction E° (V) 0.7996 Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? = Ov Ag+ (aq) + e- -→ Ag (s) O yes, there is a minimum. E %3D red Al3+ (aq) + 3e- → Al (s) -1.676 1.692 Au+ (aq) + e → Au (s) If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. O no minimum Au3+ (aq) + 3e- → Au (s) 1.498 Ba2+ (ag) + 2e- - Ba (s) -2.912 Brz (1) + 2e 2Br (aq) 1.066 - Ca2+ (ag) + 2e Ca (s) -2.868 Is there a maximum standard reduction potential that the half-reaction used at the…

3. The Eel fora galvanic cell composed of a Li electrode and an unknown electrode was found to be 2.91 volts. Use the Standard Reduction Potential table to determine the identity of the unknown electrode. Show work. Ered (Volts) -0.80 -0.34 -0.04 -0.76 -0.14 -0.40 -2.37 Half-Reaction Ag (aq) + 1e → Ag(s) Cu²+ (aq) + 2e > Cu(s) Fe (aq) + 3e > Fe(s) Zn²+ (aq) Sn²+ (aq) + 2e +2e → Zn(s) Sn(s) Cd²+ (aq) + 2e* Cd(s) Mg²+ (aq) + 2e Mg(s)

Predict reaction and calculate E°cell from standard reduction potentials. A voltaic cell is constructed from a standard AI3+|Al half cell (E°red = -1.660V) and a standard F2|F° half cell (E°red = 2.870V). What is the spontaneous reaction that takes place, and what is the standard cell potential? Spontaneous cell reaction:Write a balanced equation using the smallest integer coefficients possible. + Standard cell potential: V.

Use the References to access important values if needed for this question. A standard galvanic cell is constructed in which a Cu²* | Cu half cell acts as the cathode. Which of the following statements are correct? Hint: Refer to a table of standard reduction potentials. (Choose all that apply.) O Cu is oxidized at the cathode. O Cr3+|Cr2+ could be the other standard half cell. The anode reaction could be Cr2* -> Cr³* + e Ag"Ag could be the other standard half cell. U As the cell runs, anions will migrate from the Cu2"|Cu compartment to the other compartment. Submit Answer Try Another Version 2 item attempts remaining

A chemist designs a galvanic cell that uses these two half-reactions: standard reduction potential Exed half-reaction 2 H2O(1)+2e → H2(g)+2OH (aq) Ε red -0.83 V 2+ Zn(aq)+2e →>> Zn(s) E = = -0.763 V 'red Answer the following questions about this cell.