An as-seen-on-TV product is a non-stick pan which has been reportedly treated with diamond dust (n = 2.417). We decide to shine green light of 537.1nm on the pan and see constructive interference. The next wavelength of light we observe constructively interfere is violet light (483.4 nm). From these we deduce that order for the green light is m = 9. What is the thickness of this diamond dust layer if we assume that the ceramic underneath the diamond layer is n= 0? Determine a wavelength which would destructively %3D interfere.

Laser light of wavelength 627.0 nm passes through a double-slit arrangement at the front of a lecture room, reflects off a mirror 29.2 m away at the back of the room, and then produces an interference pattern on a screen at the front of the room. The distance between adjacent bright fringes is 9.52 cm. What is the slit separation in meters? Number i 0.000192 Units m

The picture shows the interference pattern obtained in a double-slit experiment with monochromatic light of wavelength 650 nm. The distance shown between intensity maxima is y = 4 mm.    How far away (in mm) from the central maxima is the location where the two waves have a path difference of exactly 1950 nm?

You illuminate a slit with a width of 78.9 μm with a light of wavelength 731 nm and observe the resulting diffraction pattern on a screen that is situated 2.05 m from the slit. What is the width, in centimeters, of the pattern's central maximum?

A thin film of thickness 187.5 nm and refractive index 1.6 is coated on plastic of refractive index 1.5.  Red light of wavelength 600 nm is incident normally on the film.  (a) Determine total path difference between light reflecting from the top and bottom of the film (b) Express path difference in terms of wavelength. (c) what type of interference do we have for the reflected light?

Light of wavelength 553.0 nm553.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 61.5 cm61.5 cm from the slit. The distance on the screen between the fifth order minimum and the central maximum is 1.25 cm1.25 cm. What is the width ?a of the slit in micrometers (μm)?

Light is sent through a single slit of width w = 0.52 mm. On a screen, which is L = 1.9 m from the slit, the width of the central maximum is D = 5.2 mm. a) The angle of the first dark fringe theta dark. Express sin(theta dark) in terms of the wavelength of the light λ and w. sin(theta dark) =  b) Express tan(theta dark) in terms of D and L. c) If D << L, how is tan(theta dark) related to sin(theta dark)? d) Express λ in terms of w, D, and L? e) Solve for the numerical value of λ, in nanometers.

Parallel rays of monochromatic light with wavelength 575 nm illuminate two identical slits and produce an interference pattern on a screen that is 75.0 cm from the slits. The centers of the slits are 0.640 mm apart and the width of each slit is 0.434 mm. If the intensity at the center of the central maximum is 4.20×10−4 W/m2, what is the intensity at a point on the screen that is 0.850 mm from the center of the central maximum?