an ArrayList of ArrayLists
Q: The input to this method is supposedly an ArrayList of integers that ranges from 1 to 100, however…
A: Java program to solve the given problem is below.
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A: Answer is given below .
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Q: that ranges from 1 to 100, however this is not exactly the case. Sometimes, there will be gaps…
A: Given: The input to this method is supposedly an ArrayList of integers that ranges from 1 to 100,…
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A: Actually, given question regarding wrapper classes ..
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A: Answer : Option c is the correct answer.
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A: Here is the Code
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Q: The input to this method is supposedly an ArrayList of integers that ranges from 1 to 100,…
A: the answer to the following question:-
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A: Since the programming language is not mentioned, I have done the code using Java.
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You are given an ArrayList of ArrayLists, Each inner ArrayList Contains Integers. Convert everything into streams, the outer ArrayList and the inner ones. Map over the strea, reducing each inner stream by adding all the numbers together. the final result should be an array of integers where each integer represents the summation of the inner streams
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- java Write a program to do the following: Create an ArrayList of Student. Add 7 elements to the ArrayList. Use for each loop to print all the elements of an ArrayList. Remove an element from an ArrayList using the index number. Remove the element from an ArrayList using the content (element name).Given a base Plant class and a derived Flower class, complete main() to create an ArrayList called myGarden. The ArrayList should be able to store objects that belong to the Plant class or the Flower class. Create a method called printArrayList(), that uses the printInfo() methods defined in the respective classes and prints each element in myGarden. The program should read plants or flowers from input (ending with -1), add each Plant or Flower to the myGarden ArrayList, and output each element in myGarden using the printInfo() method. Ex. If the input is: plant Spirea 10 flower Hydrangea 30 false lilac flower Rose 6 false white plant Mint 4 -1 the output is: Plant 1 Information: Plant name: Spirea Cost: 10 Plant 2 Information: Plant name: Hydrangea Cost: 30 Annual: false Color of flowers: lilac Plant 3 Information: Plant name: Rose Cost: 6 Annual: false Color of flowers: white Plant 4 Information: Plant name: Mint Cost: 4 import java.util.Scanner;import java.util.ArrayList;import…In this assignment, you will compare the performance of ArrayList and LinkedList. More specifically, your program should measure the time to “get” and “insert” an element in an ArrayList and a LinkedList.You program should 1. Initializei. create an ArrayList of Integers and populate it with 100,000 random numbersii. create a LinkedList of Integers and populate it with 100,000 random numbers2. Measure and print the total time it takes to i. get 100,000 numbers at random positions from the ArrayList 3. Measure and print the total time it takes to i. get 100,000 numbers at random positions from the LinkedList 4. Measure and print the total time it takes to i. insert 100,000 numbers in the beginning of the ArrayList 5. Measure and print the total time it takes to i. insert 100,000 numbers in the beginning of the LinkedList 6. You must print the time in milliseconds (1 millisecond is 1/1000000 second).A sample run will be like this:Time for get in ArrayList(ms): 1Time for get in…
- Write code that will accept as input the characteristics of an undefined number of different softdrinks. Each softdrink should have a colour (of the can), name and volume. • Create SoftDrink objects and store them in an ArrayList (see the Appendix) as each softdrink is entered. • Alternatively, you can use an array. Take a number of items first, create an array of that size and read in the elements. • Prompt the user to add a softdrink until they choose to quit. • Once the user quits, print out a list of the softdrinks that the user has entered, sorted first by alphabetical order of name, then by colour, then by volume (ascending order). Name your driver class Question2.java. NOTE: • You can use the built-in static sort() method in the java.util.Collections class to sort your ArrayList of SoftDrink objects. Sample I/O Enter option: (1) add soft drink (2) quit: 1 Enter name, colour and volume in ml separated by space Fanta Orange 500 Enter option: (1) add soft drink (2)…Java question Use the Iterator Pattern: Create a class called Exercise, and then, in its main method, create an ArrayList called stringArrayList. Add the following five strings to stringArrayList: “one”, “two”, ”three”, ”four”, ”five”. Then, use a for loop and the index of stringArrayList to print all these five strings out to the console. 2. For stringArrayList above, can you use an iterator to traverse the five strings inside, without using the index? 3. If change stringArrayList into a TreeSet, how do you traverse the five strings use an iterator? Implement an Iterator: 4. Create a class called StringArray that is able to store a number of String objects. Create an instance variable, String[] values, (internal data storage) of StringArray to store all the strings. 5. Create a constructor for StringArray, which is able to build an object of StringArray using the parameter. public StringArray(String[] values) 6. Make the class StringArray implements…Create an ArrayList of strings to store the names of celebrities or athletes. Add five names to the list. Process the list with a for loop and the get() method to display the names, one name per line. Pass the list to a void method. Inside the method, Insert another name at index 2 and remove the name at index 4. Use a foreach loop to display the arraylist again, all names on one line separated by asterisks. After the method call in main, create an iterator for the arraylist and use it to display the list one more time. See Sample Output. SAMPLE OUTPUT Here is the list Lionel Messi Drake Adele Dwayne Johnson Beyonce Here is the new list * Lionel Messi * Drake * Taylor Swift * Adele * Beyonce Using an iterator, here is the list Lionel Messi Drake Taylor Swift Adele Beyonce Textbook: Introduction to Java Programming and Data Structures, Comprehensive Version, Edition: 11th Author: Y. Daniel Liang Publisher: Pearson ISBN: 9780134670942
- In this programming challenge, you will create a simple trivia game for two players. The program will work like this: • Read the contents of the trivia.txt file into an ArrayList . • Starting with player 1, each player gets a turn at answering one trivia question. (For instance, if there are 10 questions, 5 for each player.) When a question is displayed, four possible answers are also displayed. Only one of the answers is correct, and if the player selects the correct answer, he or she earns a point. • After answers have been selected for all of the questions, the program displays the number of points earned by each player and declares the player with the highest number of points the winner, same as the sample execution. You are to design a Question class to hold the data for a trivia question. The Question class should have String fields for the following data: • A trivia question • Possible answer 1 • Possible answer 2 • Possible answer 3 • Possible answer 4 • The number of the…The input to this method is supposedly an ArrayList of integers that ranges from 1 to 100, however this is not exactly the case. Sometimes, there will be gaps in the range for example, the range could be: [1 2 ... 7 8 ... 99 100], with missing ranges in between. Find all the missing numbers from the range, add them to an ArrayList, return the ArrayList.------------------------ Below is my code that is failing. It is returning the correct missing numbers but is not going passed the last number from the array. so [4,5,14,16,23,76,89] It is placing all of the missing numbers up to 88 when it should be going to 100 The solution should only return the missing numbers from 1-100. The original numbers from the given array should not be included in the return. How can I only return the missing numbers? ------------------------ public ArrayList<Integer> solution(ArrayList<Integer> nums) {ArrayList<Integer> result = new ArrayList<Integer>();int count =…Use the Iterator Pattern: Create a class called Exercise, and then, in its main method, create an ArrayList called stringArrayList. Add the following five strings to stringArrayList: “one”, “two”, ”three”, ”four”, ”five”. Then, use a for loop and the index of stringArrayList to print all these five strings out to the console. 2. For stringArrayList above, can you use an iterator to traverse the five strings inside, without using the index? 3. If change stringArrayList into a TreeSet, how do you traverse the five strings use an iterator? Implement an Iterator: 4. Create a class called StringArray that is able to store a number of String objects. Create an instance variable, String[] values, (internal data storage) of StringArray to store all the strings. 5. Create a constructor for StringArray, which is able to build an object of StringArray using the parameter. public StringArray(String[] values) 6. Make the class StringArray implements Iterable So that it…
- need Urgent Requirement: There will one question related to ArrayList class similar to the following question. The following driver has created a an ArrayList of Point objects. write a method that moves all the points with the value of x greater than its value of y to the end of the list. .Create an ArrayList of strings to store the names of celebrities or athletes. Add five names to the list. Process the list with a for loop and the get() method to display the names, one name per line. Pass the list to a void method. Inside the method, Insert another name at index 2 and remove the name at index 4. Use a foreach loop to display the arraylist again, all names on one line separated by asterisks. After the method call in main, create an iterator for the arraylist and use it to display the list one more time.The input to this method is supposedly an ArrayList of integers that ranges from 1 to 100, however this is not exactly the case. Sometimes, there will be gaps in the range for example, the range could be: [1 2 ... 7 8 ... 99 100], with missing ranges in between. Find all the missing numbers from the range, add them to an ArrayList, return the ArrayList.------------------------ Below is my code that is failing. It is returning the correct missing numbers but is not going passed the last number from the array. so [4,5,14,16,23,76,89] It is placing all of the missing numbers up to 88 when it should be going to 100 ------------------------ public ArrayList<Integer> solution(ArrayList<Integer> nums) {ArrayList<Integer> result = new ArrayList<Integer>();int count = 0;for(int i = 0;i<nums.size()-1;i++){for(int j = nums.get(i)+1;j<nums.get(i+1);j++){count++;result.add(j);}}return result;}