An amusement park ride consists of a car which takes riders through a vertical loop at a constant speed of 10.0 m/s. If a rider at the top of the loop has a centripetal acceleration of 1.5 g, what is the loop's radius? (take g = 10 m/s²) 5 rider O 15/10 m = 1.5 m O 100/5 m = 20 m O 100/25 m = 4 m O 100/15 m = 6.67 m O 15 10 m = 150 m

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section5.3: Nonuniform Circular Motion
Problem 5.5QQ: Which of the following is impossible for a car moving in a circular path? Assume that the car is...
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An amusement park ride consists of a car which takes riders through a vertical loop at a constant speed of 10.0
m/s. If a rider at the top of the loop has a centripetal acceleration of 1.5 g, what is the loop's radius? (take g = 10
m/s²)
5
rider
O 15/10 m = 1.5 m
O 100/5 m = 20 m
O 100/25 m = 4 m
O 100/15 m = 6.67 m
O 15 10 m = 150 m
Transcribed Image Text:An amusement park ride consists of a car which takes riders through a vertical loop at a constant speed of 10.0 m/s. If a rider at the top of the loop has a centripetal acceleration of 1.5 g, what is the loop's radius? (take g = 10 m/s²) 5 rider O 15/10 m = 1.5 m O 100/5 m = 20 m O 100/25 m = 4 m O 100/15 m = 6.67 m O 15 10 m = 150 m
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