An alpha particle reaches 28 fm in a gold foil experiment before it lost all of its kinetic. energy. Estimate the kinetic energy of the alpha particle

Gadolinium-149 decays through alpha decay and forms samarium-145. Estimate the kinetic energy of the alpha particle.

3. a) Alpha particles of the same initial speed are shot at the same intensity toward gold, silver, and aluminum foils of the same thickness. They are observed at a detector at a fixed scattering angle, 0 0°. What would the ratios of the number of alpha particles scattered by the gold and silver foils to the aluminum foil, No Au 13). NaAl and respectively, be? (ZAu = 79, ZAg = 47, ZAI Na Ag NaAl b) Compare the number of a particles of fixed kinetic energy scattered through an angle of 10° (call this Na(10°)) with the number scattered through an angle of 20° (Na (20°)) for Rutherford scattering by a thin gold foil of fixed thickness. Compute Na (10⁰) Na (20°). p2 Rutherford's scattering model assumes that the alpha particles experience a Coulomb repulsion, F = KqZe from the nucleus of the foil's atom. If, in a head-on collision the alpha particle has enough energy to get inside a uniformly charged Kqa Zer nucleus of radius R, the force law would change to F = R³ " point-nucleus…

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