An air-standard cycle is executed within a closed piston–cylinder system and consists of three processes as follows: 1→2: constant-volume head addition from 100 kPa and 27°C to 850 kPa 2→3: isothermal expansion until ?3 =7?2 3→1: constant-pressure heat rejection to the initial state. Assuming that air has constant properties with Cv = 0.718 kJ/kg·K, Cp = 1.005 kJ/kg·K, γ = 1.4 and R=0.287 kJ/kg.K (a) Sketch the T-S and P-V diagram of the cycle  (b) Determine the ratio of the compression work to the expansion work  (c) Calculate the cycle thermal efficiency

! Required information Problem 09.034 - Ideal Otto Cycle with Variable Specific Heats - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS An ideal Otto cycle has a compression ratio of 8. At the beginning of the compression process, air is at 95 kPa and 27°C, and 760 kJ/kg of heat is transferred to air during the constant-volume heat-addition process. Take into account the variation of specific heats with temperature. The gas constant of air is R = 0.287 kJ/kg-K. Problem 09.034.a - State After Heat Addition in Variable Heat Capacity Ideal Otto Cycle Determine the pressure and temperature at the end of the heat-addition process. (You must provide an answer before moving on to the next part.) The pressure at the end of the heat-addition process is 3915.8 kPa. The temperature at the end of the heat-addition process is 1647.7 K.

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A thermodynamic cycle uses 0.5 kg of air works in a three-process air-standard power cycle:Process 1-2: Isothermal expansionProcess 2-3: Constant volumeProcess 3-1: Isentropic, k=1.4Given: Pressure and temperature at the end of constant volume process is P3=100 kPa andT3=300K, respectively. If the isentropic compression ratio is 6.0, determine:(a) The pressure, volume and temperature at each state points of the cycle.(b) The heat added and rejected throughout the cycle, in kJ(c) The work net output, in kJ(d) The thermal efficiency.(e) Illustrate the cycle in Pv and Ts coordinates.(Ans. Q1-2=157.95 kJ, Q2-3=-112.93 kJ, Q3-1=0, 45 kJ, 28.5%) Just answer D and E