A parallel plate capacitor has a capacitance of 110. pF and a plate area of 100. cm2. The space between the plates is filled with mica whose dielectric constant is 5.40. The plates of the capacitor are kept at 40.0 V. a) What is the strength of the electric field in the mica?  b) What is the amount of free charge on the plates? show complete solution

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T or F? a. For a parallel plate capacitor, the capacitance depends on the area of the plates and on the separation distance between the plates, it does not depend on the material the plates are made of. b. If a conductor is placed in an electric field, and is in electrostatic equilibrium, the electric field lines just inside the conductor will be parallel to its surface.

Area = A dielectric capacitor plates A parallel plate capacitor has each plate area as 3 cm x 4 cm, separated by a 1.0 mm thick cardboard represented by the purple layer in the figure (dielectric constant € = 3.8), is fully charged. Find the capacitance (C) and the maximum charge (Qmax) on the capacitor if it's charged with an electric field E = 16 x 106 V/m.,

The electric field between the plates of a capacitor has a strength of 200 N/C. The voltage on the left plate is positive 10 V and the voltage on the right plate is negative 10 V. What is the separation between the plates?