An A36 (Fy=248MPa) W12x79 fixed-hinged column of 5.72m length is laterally supported at mid-height on its weaker axis. If LL=2DL, calculate the maximum service Liveload in KN that the column can carry using LRFD. Use ASEP Steel Manual for WF section properties. Express your answer in 2 decimal places.
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An A36 (Fy=248MPa) W12x79 fixed-hinged column of 5.72m length is laterally supported at mid-height on its weaker axis. If LL=2DL, calculate the maximum service Liveload in KN that the column can carry using LRFD. Use ASEP Steel Manual for WF section properties. Express your answer in 2 decimal places.
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- Refer to the beam loading diagram shown If the beam is made from A992 and is continuously braced, determine the most economical member W-shape for strength only I am using AISC Steel Construction Manual 15th Edition. For the double fixed-end bend shown, the following data applies: • Service live load, P = 30 kips Required live load factor: 1.6 Beam length, L = 30 ft Self-weight has already been included. A В C 0.5L 0.5LThe beam-column shown is part of a frame not allowed to sway. The ultimate loadings on both x and y axis are shown. Use F, = 50 ksi and LRFD specs to check if W14x90 is adequate. 400k 400k 2K/ Sok-f 20 Sok-A 40ok A ookPROBLEM 4: The beam shown the figure below is a W16x31 of A992 steel and has continuous lat- eral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate. a. Use LRFD. b. Use ASD. 60k 60k W16 x 31 asap +4
- The W36 x 135 beam shown carries service loads shown (excluding weight). It has been decided to add a 10-meter steel column at point B to eliminate excessive deflection. If the column being added is fixed at the bottom and pinned at the top, design the column that can withstand as support (Use a recommended value for K. Evaluate using LRFD and ASD). a. Use WT18 section b. Use W36 section c. Using the section at (b), determine the dimension of the base plate if the foundation dimension will be 1500mm x 1500mm. Pp = 88 kN PL = 163 kN Wp = 21 kN/m WL = 58 kN/m C B 6 m 12 mASSIGNMENT #5 BIAXIAL BENDING Problem: Check the beam shown for compliance with the NSCP Specification. Lateral support is provided only at the ends, and A992 steel is used, F, = 345 mPa. The 90 kN service loads are 30% dead load and 70% live load. a. Use LRFD b. Use ASD d tw by ty 1x(106) S(10³) mm mm mm mm³ mm mmª W410x100 415 10 260 16.9 398 1920 SECTION Tx mm 177 1m 90 kN 90 KN 1.5m W410x100 I Loaded Section Ly(106) Sy(10³) Ty mmª mm³ mm 49.5 381 62.4 1m Zx(10³) Zy(10³) mm³ mm³ 2130 581O 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading condition
- topic: Compression Members An A36 (Fy=248MPa) W12x79 fixed-hinged column of 6.13m length is laterally supported at mid-height on its weaker axis. If LL=2DL, calculate the maximum service Liveload in KN that the column can carry using LRFD. Use ASEP Steel Manual for WF section properties. Express your answer in 2 decimal places.steel Design Civil Engineering Please show solutions: AW 310 x 118 section with a length of 8.0 m is used as a column. Determine the safe axial load the column can carry using AISC specifications with Fy = 345 MPa when: Properties of W 310 x 118 A = 15000 mm² rx = 136 mm ry = 77.6 mm A. column ends are fixed B. one end of the column is fixed; the other free Use LRFD Answers: A.] For Ag = 248.06X15000 100 3720,9kw $en=0.90x3720.9 = 3348.21 kW B.JPn= For Ag =40.72 x 15 000 LOW Pr= 0.90x610,81 = 549.729 KN2. A steel column 10 m long is fabricated from W section and a cover plate. Determine the safe axial load that the column can carry. Fy = 345 MPa, E = 200 GPa. Use AISC/NSCP Specs. 310 mm cover plate AY I 6 mm y2 y d1 10 m d2 W 310 x 107 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. W 310 x 107 A = 13600 mm? d = 311 mm Ix = 248x10° mm* ly = 81.2x10° mm“ d.
- Situation 4: A W12x106 simply supported beam carries a uniformly distributed load. The properties of the section relevant to the problem are as follow: Use A50 steel and Cb - 1.14 d - 328 mm bf-310 mm tf = 25.1 mm tw = 15.5 mm kdes - 40.4 mm ry - 79.0 mm lx = 388 x 10^6 mm^4 ly - 125 x 10^6 mm^4 Sx - 2380 x 10^3 mm^3 Zx=2690 x 10^3 mm^3 J-3800 x 10^3 mm^3 Cw=2870 x 10^9 mm^6 1. Which of the following nearly gives the Design Strength Moment (LRFD) if the span of the beam is 2.5m? 878 KN-m 793 KN-m 836 KN-m 811 KN mDetermine whether the D = 560 kips L = 68 kips compression member shown is adequate to support the given service loads. Take note Pu = 1.4D. 20' W12 × 79 K = 0.80, r = 3.05 in E = 29000 ksi, Fy = 50 ksi A992 steel Input Yes or No for your final answer.A 530*150 is used as a compression member with one end fixed and the other end free. The length of the column is 3.2 m. What is the nominal compressive strength if fy=350 MPa? (please help my assigment)