An 800-meter-long pipe is supposed to carry water from a 5-meter- high point to a 22-meter-high point. manometric head pressure at the outlet must be 10 meters The hydraulic slope along the pipe is 0.01. The diameter of the pipe is 30 cm and the longitudinal resistance coefficient is 0.05 = f. A. What is the required pressure at the beginning of the pipe? B. What is the flow velocity in the pipe? C. What is the flow regime in the pipe? D. Draw the lines of the hydraulic head, the piezometric head and the height along the pipe

An 800-meter-long pipe is supposed to carry water from a 5-meter- high point to a 22-meter-high point. manometric head pressure at the outlet must be 10 meters The hydraulic slope along the pipe is 0.01. The diameter of the pipe is 30 cm and the longitudinal resistance coefficient is 0.05 = f. A. What is the required pressure at the beginning of the pipe? B. What is the flow velocity in the pipe? C. What is the flow regime in the pipe? D. Draw the lines of the hydraulic head, the piezometric head and the height along the pipe

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Pressurized pipe flow

A 15-kilometer-long pipe with a pipe diameter of one meter transports water at a speed of one meter per second. The pipe has a friction coefficient of 0.005. Calculate the frictional head loss?

Question

An 800-meter-long pipe is supposed to carry water from a 5-meter-
high point to a 22-meter-high point. manometric head pressure at the
outlet must be 10 meters
The hydraulic slope along the pipe is 0.01. The diameter of the pipe is
30 cm and the longitudinal resistance coefficient is 0.05 = f.
A. What is the required pressure at the beginning of the pipe?
B. What is the flow velocity in the pipe?
C. What is the flow regime in the pipe?
D. Draw the lines of the hydraulic head, the piezometric head and the
height along the pipe

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why the head loss is not YL= f*L/D* V^2/2g ?

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