**Question 15 of 35****Select the metal with a specific heat capacity of 0.45 J/(g°C).**| Metal | Specific Heat Capacity J/(g°C) ||------------|--------------------------------|| Aluminum | 0.90 || Copper | 0.38 || Iron | 0.45 || Magnesium | 1.00 || Silver | 0.23 || Tin | 0.32 || Titanium | 0.52 |**Options:**A) FeB) SnC) AgD) Cu_Tap here or pull up for additional resources._ **Calorimetry Problem: Identifying a Metal by Its Specific Heat Capacity****Problem Statement:**An 80.0 g sample of an unknown metal, initially at 96.0°C, is placed into 150.0 g of water at an initial temperature of 26.0°C in a calorimeter. After thermal equilibrium is reached, the final temperature of the water is 28.1°C. The objective is to determine the identity of the metal based on its specific heat capacity. The specific heat capacity of water is given as 4.18 J/g·°C.**Data Table: Specific Heat Capacities of Various Metals**| Metal | Specific Heat Capacity (J/g·°C) ||------------|----------------------------------|| Aluminum | 0.90 || Copper | 0.38 || Iron | 0.45 || Magnesium | 1.00 || Silver | 0.23 || Tin | 0.32 || Titanium | 0.52 |**Task:**Using the data provided and the principle of conservation of energy in calorimetry, calculate the specific heat capacity of the unknown metal. Compare the calculated value with the values in the table to identify the metal.

The unknown metal is initially at a higher temperature, so it will lose heat on being dropped into the water. -Heat lost by the metal=Heat gained by waterHeat lost by metal:qmetal=mmetalcmetal∆Tmetalqmetal=80.0 g×cmetal×(28.1-96.0)C0qmetal=-5432×cmetal ----------(1)Heat gained by water:qwater=mwatercwater∆Twaterqwater=150 g×4.18 J/gC0×(28.1-26.0)C0qwater=1316.7 J So, 5432cmetal=1316.7cmetal=0.24 J/(gC0) This value matches with that of silver. So, the metal is silver (option C).

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An 80.0 g sample of metal, initially at 96.0°C, is placed into 150. g of water initially at 26.0°C in a calorimeter. The final temperature of the water is 28.1°C. What is the identity of the metal? (The specific heat of water is 4.18 J/g. °C.)

An 80.0 g sample of metal, initially at 96.0°C, is placed into 150. g of water initially at 26.0°C in a calorimeter. The final temperature of the water is 28.1°C. What is the identity of the metal? (The specific heat of water is 4.18 J/g. °C.)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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