Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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NMR Spectroscopy
NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra o…
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I am confused about where the 54.1 and 21.1 numbers came from because the scale is marked 2ppm to 10 ppm. I want to be able to di this myslef on a test . Can someone give me step by step instructions?

106rthw mqq S to bleitqu sasd snovbe art to omod nois CHU ZING A ¹H NMR SPECTRUM AND PROPOSING THE STRUCTURE OF A COMPOUND sqed to noitubong shutu ями STEP 1 colecular alculate interpret the HDI. zu enamuostuner skill Identify the structure of a compound with the molecular formula C₂H₁00 that exhibits the ad otni er following 'H NMR spectrum:alloon or lo amor ni bnuol onow nisqari Proton NMR 10 haped 10.2 8 6 T 54.1 Integration Values 5 AMM notor 3 21.1 ar 22.3 2ppm SOLUTION Begin by calculating the HDI. The molecular formula indicates 9 carbon atoms, which would require 20 hydrogen atoms in order to be fully saturated. There are only 10 hydrogen atoms, which means that 10 hydrogen atoms are missing, and therefore, the HDI is 5. This is a large number, and it would not be efficient to think about all the possible ways to have five degrees of unsaturation. However, anytime we encounter UD be on the l
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Transcribed Image Text:106rthw mqq S to bleitqu sasd snovbe art to omod nois CHU ZING A ¹H NMR SPECTRUM AND PROPOSING THE STRUCTURE OF A COMPOUND sqed to noitubong shutu ями STEP 1 colecular alculate interpret the HDI. zu enamuostuner skill Identify the structure of a compound with the molecular formula C₂H₁00 that exhibits the ad otni er following 'H NMR spectrum:alloon or lo amor ni bnuol onow nisqari Proton NMR 10 haped 10.2 8 6 T 54.1 Integration Values 5 AMM notor 3 21.1 ar 22.3 2ppm SOLUTION Begin by calculating the HDI. The molecular formula indicates 9 carbon atoms, which would require 20 hydrogen atoms in order to be fully saturated. There are only 10 hydrogen atoms, which means that 10 hydrogen atoms are missing, and therefore, the HDI is 5. This is a large number, and it would not be efficient to think about all the possible ways to have five degrees of unsaturation. However, anytime we encounter UD be on the l
In this spectrum, we see four signals. In order to analyze the integration of each signal, we must first divide by the lowest number (10.2): 10.2 10.2 10 <-1 Proton NMR 54.1 10.2 -5.30 21.1 10.2 2.07 The ratio is approximately 1:5:2:2. Now look at the molecular formula. There are 10 pro- tons in the compound, so the relative integration values represent the actual number of protons giving rise to each signal. 22.3 10.2 6 Chemical Shift (ppm) -2.19 22 3 there are two triplets, each with an integration of
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Transcribed Image Text:In this spectrum, we see four signals. In order to analyze the integration of each signal, we must first divide by the lowest number (10.2): 10.2 10.2 10 <-1 Proton NMR 54.1 10.2 -5.30 21.1 10.2 2.07 The ratio is approximately 1:5:2:2. Now look at the molecular formula. There are 10 pro- tons in the compound, so the relative integration values represent the actual number of protons giving rise to each signal. 22.3 10.2 6 Chemical Shift (ppm) -2.19 22 3 there are two triplets, each with an integration of
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