Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
Bartleby Related Questions Icon

Related questions

Question
### Laser Wavelength and Photon Calculation

#### Part A: Wavelength Region

A diode laser emits light at a wavelength of 988 nm. This places the laser in the **infrared region** of the electromagnetic spectrum.

#### Part B: Photon Emission Rate

The energy output from the laser is fully absorbed by a detector that records a total energy of 0.54 Joules over a duration of 34 seconds. To determine how many photons per second the laser emits, calculations must be done.

**Calculation Steps:**
1. Use the formula for energy of a photon: 
   \[ E = \frac{hc}{\lambda} \]
   where \(h\) is Planck’s constant (\(6.626 \times 10^{-34} Js\)), \(c\) is the speed of light (\(3.00 \times 10^8 m/s\)), and \(\lambda\) is the wavelength in meters.

2. Convert the wavelength from nanometers to meters:
   \[ 988 \ nm = 988 \times 10^{-9} \ m \]

3. Calculate the energy per photon.

4. Divide the total energy detected (0.54 J) by the time period (34 s).

5. Use this energy rate to find the number of photons emitted per second.

**Express your answer using two significant figures.**

#### Additional Notes

- Ensure all constants and units are correctly applied in calculations.
- Use proper significant figures and scientific notation where necessary.
expand button
Transcribed Image Text:### Laser Wavelength and Photon Calculation #### Part A: Wavelength Region A diode laser emits light at a wavelength of 988 nm. This places the laser in the **infrared region** of the electromagnetic spectrum. #### Part B: Photon Emission Rate The energy output from the laser is fully absorbed by a detector that records a total energy of 0.54 Joules over a duration of 34 seconds. To determine how many photons per second the laser emits, calculations must be done. **Calculation Steps:** 1. Use the formula for energy of a photon: \[ E = \frac{hc}{\lambda} \] where \(h\) is Planck’s constant (\(6.626 \times 10^{-34} Js\)), \(c\) is the speed of light (\(3.00 \times 10^8 m/s\)), and \(\lambda\) is the wavelength in meters. 2. Convert the wavelength from nanometers to meters: \[ 988 \ nm = 988 \times 10^{-9} \ m \] 3. Calculate the energy per photon. 4. Divide the total energy detected (0.54 J) by the time period (34 s). 5. Use this energy rate to find the number of photons emitted per second. **Express your answer using two significant figures.** #### Additional Notes - Ensure all constants and units are correctly applied in calculations. - Use proper significant figures and scientific notation where necessary.
Expert Solution
Check Mark
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY