All of its output energy is absorbed in a detector that measures a total energy of 0.54 J over a period of 34 s. How many photons per second are being emitted by the laser?
All of its output energy is absorbed in a detector that measures a total energy of 0.54 J over a period of 34 s. How many photons per second are being emitted by the laser?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Laser Wavelength and Photon Calculation
#### Part A: Wavelength Region
A diode laser emits light at a wavelength of 988 nm. This places the laser in the **infrared region** of the electromagnetic spectrum.
#### Part B: Photon Emission Rate
The energy output from the laser is fully absorbed by a detector that records a total energy of 0.54 Joules over a duration of 34 seconds. To determine how many photons per second the laser emits, calculations must be done.
**Calculation Steps:**
1. Use the formula for energy of a photon:
\[ E = \frac{hc}{\lambda} \]
where \(h\) is Planck’s constant (\(6.626 \times 10^{-34} Js\)), \(c\) is the speed of light (\(3.00 \times 10^8 m/s\)), and \(\lambda\) is the wavelength in meters.
2. Convert the wavelength from nanometers to meters:
\[ 988 \ nm = 988 \times 10^{-9} \ m \]
3. Calculate the energy per photon.
4. Divide the total energy detected (0.54 J) by the time period (34 s).
5. Use this energy rate to find the number of photons emitted per second.
**Express your answer using two significant figures.**
#### Additional Notes
- Ensure all constants and units are correctly applied in calculations.
- Use proper significant figures and scientific notation where necessary.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb31c72c-4045-4dee-afe2-8fb7977f2141%2F83662132-9b3c-4b33-8dff-add8d964777b%2Fvzhxvg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Laser Wavelength and Photon Calculation
#### Part A: Wavelength Region
A diode laser emits light at a wavelength of 988 nm. This places the laser in the **infrared region** of the electromagnetic spectrum.
#### Part B: Photon Emission Rate
The energy output from the laser is fully absorbed by a detector that records a total energy of 0.54 Joules over a duration of 34 seconds. To determine how many photons per second the laser emits, calculations must be done.
**Calculation Steps:**
1. Use the formula for energy of a photon:
\[ E = \frac{hc}{\lambda} \]
where \(h\) is Planck’s constant (\(6.626 \times 10^{-34} Js\)), \(c\) is the speed of light (\(3.00 \times 10^8 m/s\)), and \(\lambda\) is the wavelength in meters.
2. Convert the wavelength from nanometers to meters:
\[ 988 \ nm = 988 \times 10^{-9} \ m \]
3. Calculate the energy per photon.
4. Divide the total energy detected (0.54 J) by the time period (34 s).
5. Use this energy rate to find the number of photons emitted per second.
**Express your answer using two significant figures.**
#### Additional Notes
- Ensure all constants and units are correctly applied in calculations.
- Use proper significant figures and scientific notation where necessary.
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